任务：编号是1，2，……,n的n个人按照顺时针方向围坐一圈，每个人只有一个密码（正整数）。一开始任选一个正整数作为报数上限值m,从第一个仍开始顺时针方向自1开始顺序报数，报到m时停止报数。报m的人出列，将他的密码作为新的m值，从他在顺时针方向的下一个人开始重新从1报数，如此下去，直到所有人全部出列为止。设计一个程序来求出出列顺序。

要求：利用单向循环链表存储结构模拟此过程，按照出列的顺序输出各个人的编号。

测试数据：

m的初值为20，n=7 ,7个人的密码依次为3，1，7，2，4，7，4，首先m=6,则正确的输出是什么？

要求：

输入数据：建立输入处理输入数据，输入m的初值，n ，输入每个人的密码，建立单循环链表。

输出形式：建立一个输出函数，将正确的输出序列

-Tasks: number is 1, 2, ......, n of n people sitting clockwise circle, each person only a password (a positive integer). The beginning optionally a positive integer as the number off the upper limit m still start from the first clockwise order of the number of reported since 1 report m the number of stop message. The reported m people out of the line, his password as the new value of m, starting from the next person in a clockwise direction from a number of reported again, and so on, until all the columns so far. Design a program to derive the column order.

Requirements: one-way circular linked list storage structure to simulate this process, the number of individuals in accordance with the order of the columns output.

Test data:

the initial value of 20 m, n = 7, 7 personal password followed by 3,1,7,2,4,7,4, first of all m = 6, then what is the correct output?

Requirements:

Input data: input processing input data, enter the initial value of m, n, enter a password for each person,