搜索资源列表
br_fdb
- Forwarding database Linux ethernet bridge
br_stp
- Spanning tree protocol generic parts Linux ethernet bridge- Spanning tree protocol generic parts Linux ethernet bridge
br_stp_if
- Spanning tree protocol interface code Linux ethernet bridge- Spanning tree protocol interface code Linux ethernet bridge
br_sysfs_br
- Sysfs attributes of bridge ports Linux ethernet bridge
br
- ethernet network bridge for linux v3.0.1
br_sysfs_if
- Sysfs attributes of bridge ports Linux ethernet bridge
br_if
- Userspace interface Linux ethernet bridge.
tsi108_pci
- Linux Network driver, Common routines for Tundra Semiconductor TSI108 host bridge.
sjsqxtyly
- 单极性H桥DC-DC逆变电路仿真，结果正确，输出波形好-Unipolar H-bridge DC-DC inverter circuit simulation, the result is correct, the output waveform
dc_singleloop
- 基于psim9.0的直流电动机转速闭环仿真，采用整流桥给直流电动机供电-DC motor speed psim9.0-based closed-loop simulation, rectifier bridge power supply to the DC motor
fixup-ip32
- O2 has up to 5 PCI devices connected into the MACE bridge.
ZhuLan
- 计算悬索桥主缆集度的小程序,用于悬索桥总体设计时主缆面积的估算,迭代精度比较高-Small program to calculate the degree of Main Cable for the overall design of the suspension bridge main cable area estimates, iterative relatively high accuracy
holly
- Board setup routines for the IBM 750GX/CL platform w/ TSI10x bridge
npnqudong
- 此功能为实现pwm控制直流电机的正反转、调速，在驱动H桥式电路方面的c语言编程。-This function is to achieve the pwm control the positive DC motor, speed, drive the H-bridge circuit, c programming language.
mce-apei
- Bridge between MCE and APEI driver
Atmega16-PWM
- 用AVR单片机Atmega16产生两路互补的PWM波去控制全桥逆变电路的程序-Two complementary PWM wave to control the program of the full-bridge inverter circuit with AVR Atmega16
pci_v3
- PCI functions for V3 host PCI bridge
RLC_meter
- DIY RLC数字电桥【程序+电路图+BOM】 1、能够准确测量电抗器的L、C、R，精度优于0.5 ，如果进行人工逐档校准，精度优于0.3 2、取材容易，电路简洁，易于制作，成本应适当控制。使之具有更强的业余DIY价值及研究价值，并通过设计、DIY学习到LCR电桥的相关细节、原理。 -DIY digital RLC bridge program+ circuit+ BOM] 1, can accurately measure the reactor L, C, R, accur
code
- 处理lasso regression。 使用stochastic Markov property。-Algorithm for solving the Lasso problem: 0.5* (y- X*beta) *(y- X*beta)+ lambda* ||beta||_1 where ||beta||_1 is the L_1 n
spider-pic
- External Interrupt Controller on Spider South Bridge