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neibolan
- 逆波兰表达式求值问题 1.基于堆栈的基本操作。 2.若表达式正确,界面自动输出后缀表达式的值,否则输出表达式错误的信息,将结果置为0。 3.操作数和操作符均由键盘键入。-Reverse Polish expression evaluation questions 1. Based on the basic operation of the stack. (2) If the expression is correct, the interface is automatica
5.13
- 编写一程序,将两个字符串连接起来,结果取代第一个字符串。-Write a program that will connect the two strings, the result replaces the first string.
Full2012
- 1. 本研究利用 PCA 对可见-近红外(450~1 000 nm)、可见光(450~780 nm)和近红外(780~1 000 nm)光谱区域的苹果高光谱图像数据进行降维,获得 PC 图像,通过对 PC 图像进行分析,确定可用于分割损伤和正常区域的有效光谱区域,对比分析几个光谱区域的 PCA 的效果。-but currently no practical system for detecting blood spots and dirt stains exists. In order to
RCC
- 核查的关键在于对核材料属性准确、有效地识别[1][2]。利用252Cf作为随机脉冲中子源,对其入射核材料所产生的诱发裂变中子脉冲信号进行采集、处理和分析,得到自相关、互相关、自/互功率谱、功率谱密度比等一系列参数,从而反演核材料内部的反应性的情况,便可用于分析和识别核材料,其基本原理就是252Cf中子源驱动噪声分析测量法[-The result shows that the trained Elman neural network is able to identify the characte
matrix
- 矩阵(二) 编写C++程序完成以下功能: (1)假定矩阵大小为4×5(整型); (2)矩阵空间采用new动态申请,保存在指针中; (3)定义矩阵初始化函数,可以从cin中输入矩阵元素; (4)定义矩阵输出函数,将矩阵格式化输出到cout; (5)定义矩阵相加的函数,实现两个矩阵相加的功能,结果保存在另一个矩阵中; (6)定义矩阵相减的函数,实现两个矩阵相减的功能,结果保存在另一个矩阵中; (7)动态申请三个矩阵:A1、A2、A3; (8)初始化A1、A2;
medo
- 设X[ 0 : n - 1]和Y[ 0 : n – 1 ]为两个数组,每个数组中含有n个已排好序的数。找出X和Y的2n个数的中位数。 编程任务 利用分治策略试设计一个O (log n)时间的算法求出这2n个数的中位数。 数据输入 由文件input.txt提供输入数据。文件的第1行中有1个正整数n(n<=200),表示每个数组有n个数。接下来的两行分别是X,Y数组的元素。结果输出 程序运行结束时,将计算出的中位数输出到文件output.txt中-Let X [0: n- 1
Niudun
- 牛顿迭代法方程,可以计算出牛顿迭代法的结果-Newton iteration equation, we can calculate the result of Newton iteration
SQLRunnerShare
- Oracle Utilite for: 1. Run SQL queries with different sets of parameters 2. Export result to xls and sending by mail 3. Sending notification by SMS depending on: Odac, DevExpre-Oracle Utilite for: 1. Run SQL queries with different sets of
chengjitoonjifenxi
- 就是个成绩的统计分析的编程,挺好用的,建议大家-Is a result of the statistical analysis of programming, very good use, it is recommended that you use with
2
- 1)定义一个长度为10的int数组nArr,采用给定初始值或从键盘输入的方式给数组的10个元素赋值;定义一个int *型指针变量pInt,并将nArr的首地址存入pInt中; 2)功能1:将从键盘输入的0..9间两个数存入i, j,交换下标为i, j的两个数组元素中存放的内容,并输出交换前与交换后的结果; 3)功能2:通过指针间接运算,重新交换数组元素i, j中的内容,并输出交换后的内容。 4)功能3:以8位16进制数的形式输出pInt,pInt + i, pInt + j的值,并
Renyi_simulate
- 使用m文件产生加噪声的射频信号,通过滤波得到中频信号和基带信号,然后对其取倒谱。经过门特卡罗仿真,采用统计方式,得到各点的概率分布律,然后计算结果的香农熵和互雷尼信息熵。-M files generated using the RF signal plus noise, obtained by filtering the IF signal and baseband signal, and then take its cepstrum. After the door Monte Carlo si
atloutlookbar_demo
- VC++实现左边抽屉窗口类,可用作界面设计,是个支持多级分类的菜单,源码包内附有调用例子,最终效果是左边抽屉窗口,右边是视图,在很多软件中用到这种界面,我想对大家设计VC窗体界面是有帮助的。-VC++ drawer window class left, can be used as interface design, is a multi-level classification menu source package, with examples of call, the final resu
binary_sum
- 输入两个十进制数,将他们转化为二进制数进行相加,将所得结果在转化为十进制数-Enter the two decimal number into a binary number them are summed, the result will be a decimal number in the transformed
EXEInfo
- Sample Code to parse PE-header of PE-files using WinAPI only. All dialog parts coded without standard VCL Libraries, so it s good way to have very small result executable file (approx. 20 kb).
Lottery
- Input Lottery and Ticket number /Show the result of Ticket/Defining all the Functions in the class lottery./define the class : lottery
searchengine
- 简单的搜索引擎模型,通过一个词库文件来建立词库,并将词库文件的解析结果输出到文件,-Simple search engine model, the file to create a thesaurus dictionary, thesaurus file and outputs the analysis result
BingForScan
- 条码扫描提醒功能,自动保存扫描结果,实用的很哦-good tools for scan and records the scan result
QtOracle
- 本人在windows下编辑qt生成dll文件后,在本地连接oracle都没有问题,结果一发布,在其他机器就无法进行连接,最后经过发现,生成的dll,不能放到当前目录下,应放到sqldrivers目录下。-I edit in windows qt dll files generated in the local connect oracle, no problems, the result of a release, the other machine will not be able to co
Homework1
- 编写一个求方程ax2 + bx + c = 0的根 的程序,用3个函数分别求当b2-4ac大于零、等于零、和小于零时的方程的根。要求从主函数输入a,b,c的值并输出结果。 -Write a demand equation ax2+ bx+ c = 0 root program, with three functions are required when b2-4ac is greater than zero, zero, and the roots of the equation is les
Two-stage-method-solving-LP-problems
- 课堂实验,用C语言编写的两阶段法解决LP问题,里面有两个例子,附带结果,适合初学者学习使用。-Classroom experiment, the content are the two stages of C language to write the LP method to solve the problem, there are two examples, taught you how to, with the result that is suitable for beginners t