先确定二分法的上下两个端点值,这个在figure的subplot(121)中确定。 然后进行循环求解。 -confirmed dichotomy in the next two endpoint value, The figure in the subplot (121) identified. Then cycle solution.

empirical formula with kaiser clc clear all fs=1000 fc=250 df=50 r=0.001 f=fc/fs dw=2*pi*(df/fs) a=-20*log(r) n=floor(((a-8)/(2.285*dw))+1) if a>50 b=0.1102*(a-8.7) elseif a>=21 && a<=50 b=0.5842*((a-

empirical formula with kaiser clc clear all fs=1000 fc=250 df=50 r=0.001 f=fc/fs dw=2*pi*(df/fs) a=-20*log(r) n=floor(((a-8)/(2.285*dw))+1) if a>50 b=0.1102*(a-8.7) elseif a>=21 && a<=50 b=0.5842*((a-

平坦衰落，Matlab仿真程序，平坦衰落信道的MATLAB仿真(subplot(2,1,1),plot(20*log10(abs(h1(1:10000)))))