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feng1
- 此程序是解决同步与互斥的程序源代码,同时也是通过进程,和选择不同的进程,如消费者和生产者,输入不同的字符,来决定将执行哪一个进程。-this procedure is to solve and coordinate the program's source code, but also through the process, and the choice of different processes, such as consumers and producers that the
加锁法 解决两个进程合作累加数组
- 用加锁的方法解决两个进程累加数组的互斥问题-locked with two ways to solve the array of cumulative process Mutual Exclusion
Philosophers
- 哲学家进餐问题,进程是独立参与分配资源的最小单位,在有线程的OS中,线程是运行的最小单位, 课堂所述进程之间的同步与互斥,实际上是属于不同进程的线程间的同步与互斥,当 然,属于同一进程的不同线程一样存在同步与互斥,其控制同步与互斥的原理跟进程 是一样的-dining philosophers problem, the process is independent participation in the allocation of resources as the smallest
生产者消费者问题
- 进程管理中的生产者消费者问题 只要是是描述进程管理中生产者与消费者在共享文件时是否同步与互斥问题-management process, the producer consumer issues as long as it is described process management producers and consumers when sharing files synchronized with the Mutual Exclusion
读者与写者
- 操作系统实验,进程同步与互斥读者写者问题,用vc实现-experimental operating system, and coordinate the process of the readers who wrote, using vc achieve