个函数的功能是构建一个 n 项的菲波那契数列-A function of its functions is to build a n of the Fibonacci series

利用函数和递归做一个数列的加减运算，数列的加减运算有一定的规律，可利用函数与计算出结果-The constant  can be calculated by the infinite series:  = 4- 4/3+ 4/5- 4/7+ 4/9- 4/11+.... Write a C program that uses a do/while loop to calculate  using the series. The program

计算一个数列的众数，即出现次数最多的那个数，要求尽量低的时空复杂度-calculate a series of the plural, that is the highest number that the number of requests time and space as low complexity