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huiwenshu
- 关于回文数的代码 很简短 可以用于数字于字母 嘻嘻^_^ -Palindrome on the number of code can be very brief in the alphabet for digital hee hee ^ _ ^
aba
- 试写一个算法判别读入的一个以‘@’为结束符的字符序列是否是“回文”-try to write an algorithm for the discriminant read into a '@' website at the end of the sequence of characters is whether the "Palindrome"
1112333
- 随便输入一个数活一个字符串，能够判断输入的是否为回文数，即从左边读过来和右边多过来一样-casually importation of a few live a string, to determine whether the imported downfall, that is read from left to right and up over the same
lff
- 这是判断回文的程序-This is the procedure judgment Palindrome
018
- 用于判断正整数n的d进制数表示形式是否是回文数-tell the positive integers n is a Palindromic Number
CostforIdeal
- 判断字符串是否可以构成回文串，如果可以，将该字符串转为回文串形式，并求出最小交换次数，必须是相邻符号间交换。-To determine whether the string can constitute a palindrome string, and if so, the string is palindrome strings to form and find the minimum switching frequency, must be exchanged between adjacen
huiwen
- 1. 判断一个数据、字符串是否为回文； 2.可以支持多组判断。-1. To judge a data string is a palindrome 2. Can support multiple sets of judgments.
he
- 回文判断，具体回文是什么我也忘了，不过此程序绝对是正确的啊-Palindrome determine the specific palindrome is what I have forgotten, but this program is absolutely correct ah
Palindromes-judgement-CSharp
- 基于C#+winform开发的“回文判定”程序：对于一个从键盘输入的字符串，判断其是否为回文。回文即正反序相同。如“abba”是回文，而“abab”不是回文。此判定程序包含了三种判定方法：1、根据数组元素；2、利用栈先进后出，队列先进先出的特点3、分段检测。（已给出完整的代码注释）-Based on C#+ winform development "palindromes judgement" program: for a keyboard input from the string, deci
sicily3
- 输入一个字符串（字符串的长度不超过100），求出其中最长的回文子串的长度。子串的含义是：在原串中连续出现的字符串片段。回文的含义是：正着看和倒着看相同，如abba和yyxyy。-Enter a string (the length of the string is not more than 100), calculated the length of the longest palindrome substring. The substring meaning: the string frag
p
- 此程序采用直接生成回文数的方法，高效地实现回文素数问题-This program uses a direct method to generate palindrome, palindromic primes efficient implementation issues
777
- 证明任意一个数字，加上自己的逆序，反复多次都可以组成回文数-Prove any one figure, coupled with their own reverse, can be repeatedly composed palindrome
HuiWenTest
- 用JAVA语言判断是不是回文，有几位数字并且输出出来。-JAVA language judgment is not a palindrome, several digital and outputs it.
shujujiegou
- 1． 实验目的：掌握栈与队列的基本结构和操作方法，并能利用其解决实际问题。 实验内容：假设称正读与反读都相同的字符序列成为“回文”，试写出一个算法判别输入的一个以“@”为结束符的字符序列是否“回文” -1. Experimental Objective: To master the stack and queue the basic structure and methods of operation, and can use them solve practical problems.
some-cPP-algorithm
- 一些简单常见的c++算法，包括：求奇数平均值，判断回文数，求汉诺塔-Some simple common c++ algorithms, including: seeking odd average judge palindrome, seeking Tower of Hanoi
HuiWen_Test
- 用户输入一串文字，系统将自动完成回文效果-Input some sentences by user and Sys will put it into palindrome effect
huiwen
- 给出某个英文单词，验证英文单词是否是回文(Verify that the English word is palindrome)
NET_Source
- 是LogOutputSocketProtocol的管理对 象；m_uploadSocketProtocolMgr是UploadSocketProtocol的管理对象，用于检测是否同时上传同一个文 件；m_downloadSocketProtocolMgr是DownloadSocketProtocol的管理对象；m_daemonThread 是守护进程，用于关闭超时连接。 2. AsyncSocketUserToken：用于SocketAsyncEventArgs绑定，保存 每个Socket服务