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hermit
- 在求n阶差商时,考虑有重节点的情况,使用Hermite插值法-seeking to n-poor, consider the weight of the nodes, the use of Hermite interpolation
duoxiangshi
- 多项式和、差、积、商（余数）四则运算，winform,C#实现-Polynomials, difference, product, quotient (remainder) arithmetic, winform, C# implementation
Cpp1
- 牛顿差商表 ，可输入节点计算 之后再继续添加结点计算~-Newton divided difference table, after calculating the input node can then continue to add nodes to calculate ~