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- 编程找出10000以内所有的回文数的平方仍是回文数的数。所谓回文数是指左右数字完全对称的自然数，例如：11，121，1221等都是回文数。-All of the programming find within 10,000 square is still the number of reported the number of reported. So-called palindromes number refers to the specified number of symmetrical
test2
- 老师让我们写个回文数的小程序，* 题目分析与算法设计 对于要判断的数n，计算出其平方后(存于a)，将a的每一位进行分解，再按a的从低到高的顺序将其恢复成一个数 k(如n=13，则a=169且k=961)，若a等于k则可判定n为回文数。-Let the teacher write a palindromic number of small programs,* the subject analysis and algorithm design is to determine the n
huiwenshu
- 输入一个字符串，如果这个字符串时对称的，则说明这个数十回文数，否则不是-Enter a string, if the string symmetry, then the dozens of palindromic number, otherwise not
huiwen
- 实现了一段字符是否为回文的判断《数据结构》-huiwen
huiwen
- VB环境做的回文数判断，初级的简单东西，自己做的-VB-palindromic done to determine the number of primary simple things, doing their own
MyProject
- C++程序设计实验题 回文 矩阵转换 矩阵最大值最小值问题 分配内存释放内存模仿 统计字符数目 -c++ execise
huiwen
- 功能：检查字符串是否为回文（即正序与逆序一样）字符串 -Features: Check string is a palindrome (that is, with the reverse sequence is the same as) the string
huiwenpanduan_seqlist
- 自己写的一个回文判断的程序，用C语言写成，用了线性表的顺序存储方式，能够正确判断一个字符串是否回文。-Write a palindrome program to judge, with the C language written in the order of the table with the linear storage method to correctly determine whether a string is palindrome.
huiwen
- 回文，求一个数字是否是回文，中间含有一个函数，然后可以进行判定-Palindrome, is seeking a number is palindrome in the middle contains a function, and then can be determined
huiwen
- 回文判断：输入一串字符，根据它的对称性，判断该字符串是否为回文-Palindrome
codingraph
- 能够方便的做回文判断操作，希望对大家学习有用！-huiwen
ProblemAPalindrome
- 解决一道简单的判断回文结构的题目，对C++的栈结构有更好的了解-Solve a simple palindromic structure to determine the subject of C++, a better understanding of the stack structure
reverse
- 输入一个字符串，程序判断输出是否为回文字符串-Enter a string to determine whether the palindrome string
4_14huiwen
- 求出100--500内的所有满足下述条件的"回文数"（正读与反读大小相同的数为 "回文数"）：该数的3位数字之和大于等于10-Find 100- 500 all meet the following conditions within the " palindrome" (read anti-right reading and the number of the same size as the " palindrome" ): This 3-digit n
hiwenzichuan
- 回文串的源代码，大一学生可以看看啊，最基本的-Palindromic string of source code
dfdfdsd
- 判断回文数,很不错的易语言源码，易爱好者可以下载使用-Determine palindrome, a very good source of easy language, easy to use fans can download
huiwenshu
- 回文数 回文数 回文数 回文数 回文数 回文数-Palindromic function Palindromic functionPalindromic functionPalindromic functionPalindromic functionPalindromic functionPalindromic function
cs98876
- 易语言源码分享。希望更多的朋友了解易语言。源码名称：判断回文数。体验中文编程-Easy language source code sharing.Hope more friends to understand easy language.Source Name: judgment palindrome number.Chinese programming experience
huiwen
- 对回文数进行管理，abccba以及abcba都是回文数。-Palindrome the management, abccba, as well as abcba palindrome.-
chengxu
- 求11--999之间的回文数 比较实用 大家可以放心下载-failed to translate