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duo
- 第一步：10格插件 1.将7.5SP2首页10格插件直接上传根目录覆盖 2.后台关闭首页热榜、否则会显示2个首页10格 第二步：个人信息美化 1.将图片文件夹里的文件直接上传覆盖 2.将懒人包解压出来的文件read.php上传到根目录 3.将read上传到template/wind/覆盖 另外送大家都喜欢的论坛提示音。*您的有的消息请注意查收* 将文件传到wwwroot/images/wind/覆盖 完成！-The first step: 1
faceeditapp
- C++在RichEdit中使用诸如表情一类的图象类，VC6和VC7两个版本的都有，示例程序同样支持两种环境，编译无错，请将编译后的EXE文件拷贝至项目根目录下运行，以便于程序能调用res目录中的资源文件-C++ in the RichEdit using images such as the expression of a class type, VC6 and VC7 have two versions, sample programs also support both environmen
5_1
- 一些有用的C语言小程序：输入以秒为单位所表示的时间，试将其换算为几日几时几分几秒；输入一个华氏温度，输出对应的摄氏温度，要求输出结果保留两位小数；输出a、b两数中的较大值；输入一个年号，判断该年是否闰年，并输出判断结果；求一元二次方程的根，系数a、b、c由键盘输入-Some useful C-applet: input in seconds the time indicated, try to convert a fraction to a few days when a few seconds
ysq1
- 本计算器可实现加减乘除，绝对值、三角函数，开方次方等功能，用户根据提示输入欲执行的操作，计算器便可输出相应的结果-The calculator can be realized, Math, absolute value, trigonometric, square root th power functions, the user prompted want to execute under the operation of calculator will output the correspo
fusion
- 配电网规划必须满足辐射性和连通性，配电网扩展规划问题随机产生的初始群体中往往存在大量不可行解，采用根节点融合法可确保方案的可行性。-Distribution network planning must meet radiation and connectivity, distribution network expansion planning problem with randomly generated initial population there is often a large nu
homework
- 已知一棵排序二叉树，树中结点的形式为： data info left right 其中，data 给出结点的数据场，info 给出本结点的左子树中的结点总数，left和 right 分别给出本结点的左儿子和右儿子的地址。数据场data 和info的类型皆为 int。又已知该二叉排序树的根结点的地址为 root。请设计二个函数，分别实现下述功能： 1． 按递增序找出该二叉排序树中的第 i 个小的结点。 2． 插入数据场之值为 x 的结点，并仍应保持
lagrange
- Python:Inverse quadratic interpolation for root of a function-Python: Inverse quadratic interpolation for root of a function
CCS20
- ccs2.0源码 还原根目录下的data.bak数据库 在Web.config中配置SiteSqlServer的数据库连接 设置IUSR用户可写网站目录； 在站点中建立html的asp.net映射-ccs2.0 restore the root directory of the source database in the Web.config data.bak configure the database connection settings SiteSqlServer
12_1
- 编写一个程序，求给定数的平方根，并用异常处理机制检测负数的情况-Write a program, the square root of the given number, and testing negative with exception handling the situation
wubizigen
- 45分钟五笔字根倒背如流：通过字母与对应字根挂钩联想，将字根跟字根联想-45 minutes Wubi memorized root: root linked with the corresponding through letters Lenovo, Lenovo will root with the root
CA.root
- package and describe
1
- Computer Simulation Results and Analysis for a Root Raised Cosine
jisuanqi
- VC实现的简单计算器，可进行加减乘除、开平方等运算-VC to achieve a simple calculator for addition, subtraction, square root and other operations
calculator
- 全功能计算器,基本运算都能满足!既包括加/减/乘/除,还有开方等等!-Full functional calculator, basic operations can be satisfied! Includes both add/down/take/besides, still have root wait!
Calculater
- 我编写的一个简易计算器。实现基本运算、乘方开方等功能。-I wrote a simple calculator. For basic computing, power and square root functions.
GetEquationRoot
- 一元二次求根，考虑得比较全面。比如方程有两个不同的实根，两个相同的实根，两个虚根，方程退化成一元一次方程，以及无解的情况。最后根的显示也使用一个小小的技巧 小程序不复杂，但是未必每个人第一次都能做的很完善 -Quadratic root finding, may be considered more comprehensive. Such as the equation has two different real roots, two identical real roots, two ima
ghfsh
- 1由先序序列确定根节点（即第一个字母） 2按根节点把中序序列分为两段，前面是左子树，后面的是右子树 后面的步骤就基本是前面两步的重复*/ -1 determined by the sequence of the first order root (ie the first letter) 2 sequence at the root node in the sequence to be divided into two sections, in front of the left s
jisuanqi
- VC++6.0简单计算器，有加减乘除和开方运算，适合新手-VC++6.0 simple calculator, with addition, subtraction and root operation, suitable for beginners
Hydrus
- ONE-DIMENSIONAL VARIABLY SATURATED FLOW AND TRANSPORT, INCLUDING HYSTERESIS, ROOT WATER UPTAKE AND NONLINEAR SORPTION-ONE-DIMENSIONAL VARIABLY SATURATED FLOW AND TRANSPORT, INCLUDING HYSTERESIS, ROOT WATER UPTAKE AND NONLINEAR SORPTION
Calculator
- VC++编写的又一个小型数学计算器，能进行基本的加减乘除运算，除此之外，还可以进行平方根运算，还具备清屏功能。VC++的初学者供参考，高手可路过~-Written in VC++ has a small mathematical calculator that can perform basic addition and subtraction, multiplication and division, in addition to the square root, but also has c