可灵活输入3个数据，根据已有公式CA[i]=13.7*MR[i][2]-5.76*MR[i][1] CB[i]=25.80*MR[i][1]-7.60*MR[i][2]；CC[i]=4.695*MR[i][0]-0.268*(CA[i]+CB[i]) 计算得到CA，CB，CC叶绿素-input three random integers, and the program would output CA,CB,CC using the following formula:CA[i]=13.7*MR

自己编写的关于CB观测器例子的程序，非线性那个有点不足-I have written on CB observer program examples