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自适应(Adaptive)神经网络源程序
- 自适应(Adaptive)神经网络源程序 The adaptive Neural Network Library is a collection of blocks that implement several Adaptive Neural Networks featuring different adaptation algorithms.~..~ There are 11 blocks that implement basically these 5 kinds of
Adaptive
- The adaptive Neural Network Library is a collection of blocks that implement several Adaptive Neural Networks featuring different adaptation algorithms.~..~ There are 11 blocks that implement basically these 5 kinds of neural networks: 1) A
hanoisea
- 该程序用非递归的方法实现了汉诺塔问题的求解。当源盘的数目较少时该算法的执行速度比递归算法快，但当源盘块数较多时递归算法执行速度块-the program with non - recursive method of the Tower of Hanoi problem solving. When the source of the relatively small number of sites at the time of the algorithm implementation rate f
exa130401
- 本程序先生成一个“Blocks”信号，然后加上高斯白噪声，再用 db3 小波进行分解， ％ 以说明信号和噪声在各个尺度上的表现。-this program as a "Blocks" signal, then add white Gaussian noise, reuse db3 wavelet decomposition,% to illustrate signal and noise in various scales performance.
Bastile
- XC的儿子小XC最喜欢玩的游戏用积木垒漂亮的城堡。城堡是用一些立方体的积木垒成的，城堡的每一层是一块积木。小XC是一个比他爸爸XC还聪明的孩子，他发现垒城堡的时候，如果下面的积木比上面的积木大，那么城堡便不容易倒。所以他在垒城堡的时候总是遵循这样的规则。小XC想把自己垒的城堡送给幼儿园里漂亮的女孩子们，这样可以增加他的好感度。为了公平起见，他决定把送给每个女孩子一样高的城堡，这样可以避免女孩子们为了获得更漂亮的城堡而引起争执。可是他发现自己在垒城堡的时候并没有预先考虑到这一点。所以他现在要改造城
hanoi
- 汉诺塔代码,从第一个木桩中,把所有盘子从大到小搬移到第三个木桩中.-HANOR code from a wooden blocks, all the dishes to the smallest movement pickets were third.
Nn564
- The adaptive Neural Network Library is a collection of blocks that implement several Adaptive Neural Networks featuring different adaptation algorithms.
OptimizationTipsandTricks
- New users and old of optimization in MATLAB will find useful tips and tricks in this document, as well as examples one can use as templates for their own problems. Use this tool by editing the file optimtips.m, then execute blocks of code in cel
FluidPipelineSimulinkModels
- These Simulink blocks contain transfer functions that model the pressure and flow transients for axisymmetric 2D viscous flow of a compressible fluid in a straight rigid circular cross section pipelines. Three models are available: (1) pressure
powerelec1
- 电力电子环流SIMULINK模型 Notice that the Thyristor blocks have an output identified by the letter m. This output returns a Simulink vectorized signal containing the thyristor current (Iak) and voltage (Vak).
blocksandnoisdopp
- 1.对染噪doppler信号进行小波包3层分解：分解层次j=1,2时，都是信号的概貌；当j=3时，反映概貌的已几乎不含噪声分量，而其它噪声分量的幅值已很小。 2.对加噪Blocks信号进行不同阈值及不同阈值的使用方式降噪。
hyplas
- ************************************************************************ * * * * * THIS IS THE H Y P L A S 2.0 README FILE * * ----------------- * * * * HYPLAS is a finite element program for implicit small and large * * strain analisys of hyperelast
workingjpeg.zip
- JPEG DCT based baseline method which divides the image into 8x8 blocks and quantize anthen entropy coded.,JPEG DCT based baseline method which divides the image into 8x8 blocks and quantize anthen entropy coded.
FSKMOD
- FSK modulator, very easy and simple to make, made on blocks and well detailed.
barplot
- An example C-file S-function for accessing simulink signals * without using the standard block inputs. In this case, a floating * bar-plot style scope is implemented. The signals that are selected * on the diagram (via the mouse) are display
block_mp
- 压缩感知里面的稀疏重建问题，在原来MP的算法的基础上，提出了分块的思想，即将原子库分块后，测试算法的性能。-Compressive sensing is refered as the block sparse algorithm is described,that is based on the original MP algorithm,and the atom libruary is divided into blocks ,and the performance is testified.
block4x4
- divide the image in to sub blocks
piii
- dividing image into blocks and calculatind pixel ratio
uwb_lib
- I want to simulate a MB-OFDM-UWB system in Matlab. I did pure OFDM system before which consist of convolution code block, modulation block, FFT block, Cyclic Prefix block, multipath block and corresponding receiver blocks. However, how to modif
Blocks
- clc close all clear all I=imread( desert.jpg ) [r c]=size(I) bs=16 Block Size (8x8) nob=(r/bs)*(c/bs) Total number of 8x8 Blocks Dividing the image into 8x8 Blocks kk=0 for i=1:(r/bs) for j=1:(c/bs) Block(:,:,kk+j)=I