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mapc
- 计算子午圈半径M 计算卯酉圈半径N 计算玮圈半径r 计算经线弧长Sm 计算纬线弧长Sn 计算球面梯形面积 计算最大角度变形 计算球面极坐标-calculated Meridian circle radius circle conveniently calculated M N calculation Wei radius circle radius r calculated meridian arc Sm calculated latitude arc
circle_wyb
- (1) 用浮点数定义2 个几何量m1 和m2;m2 的缺省值为0.0。 (2) 实现2个构造函数:允许用1 个参数或2个参数声明几何对象。用1 个参数r 声明 的几何对象为半径为r 的圆;用2 个参数r1 和r2 声明的几何对象为r1´ r2 的矩形。所声明 的几何对象的中心在原点。 (3) 定义计算几何对象的面积,周长和对角线长度的成员函数。 (4) 对于给定的实数r,先声明一个半径为r 的圆c1;然后声明一个c1 的外切矩形s, 接着再声明s的外接圆c2。
Hexagon
- Hexagon is a C++ function that returns a complex number which represents a randomly distributed location within a hexagon. The orientation of the hexagon is with vertical sides, where R is the radius supplied to the function. A test bench showing
hartigansSLC_OpenCV
- hartigans Sequential Leader Clustering Algorithm in terms of OpenCV (ver.1.1) Sequential Leader algorithm: Hartigan, J. A. (1975), Clustering Algorithms. John Wiley and Sons, Inc., New York, NY. 1. Select maximum cluster "radius" 2
HoughObject
- Circles We can extend the Hough transform to other shapes that can be expressed parametrically. For example, a circle of fixed radius can be described fully by the location of its center (x, y). Think of each feature (edge) point on the circle
code
- 从键盘输入两个矩阵,输出这两个矩阵和这两个矩阵相乘的矩阵,图书管理系统的一小部分 要求能 登陆 注册 推出 登陆要有次数限制(失败三次退出程序等),注册信息要求写入到文本文件里保存,已知圆半径r=2.5 圆柱高h=4,求圆的周长,面积,圆球体积,圆柱体积,用cin输入要计算的项目,然后输出计算结果,输入输出时要有文字提示,求1!+2!。。。+10!c语言代码,贪吃蛇游戏的C语言代码,求几个带权字符的哈夫曼编码,本打字游戏可进行英文,其它字符和全部字符的打字训练,每次训练若干个字符并进行打字时间,
ExpandingRods
- 题意:已知一个圆的弦长l0及这条弦所在的弧长l1,求弦的中心点到弧的中心点的距离 思想:这是一个列方程然后利用二分法解方程的题目,令该疑弧所对的圆心角为anlg, 半径为r,根据题意有两个方程:l1=anlg*r l0=2*r*sin(anlg/2) 两个方程两个未知数, 通过化简有:2*l1*sin(anlg/2)-anlg*l0=0 因为角度的值是从0到2*pi,题目中讲到过 弧的长度不可能大于弦的两倍,所以角度不可能取到2*pi,但是有可能为0,把零特殊考虑, 再从0到
roundCenter
- vc2008 dos 程序 已知AB两点坐标,半径R。 求2个圆心。 公式使用MATLAb推导的,做了一点简化,和小的改动。 都在函数 double jisuanYanxin(double Ax,double Ay,double Bx,double By,double R) 里面-vc2008 dos program known AB two coordinates, radius R. Seeking two center of the circle. Formula de
BallFretting190809
- This tool is a simplification of the ballpivoting algorithm. It imagines a bella eating a delaunay traignulation in order to extract a manifold surface. It requires a single parameter: radius of the fretting ball. Ball Fretting Given a unif
cylinder2
- [X,Y,Z]=cylinder2(x,y,z,r,N,o) 向量X,Y,Z轴定义圆柱面中心线 和矢量r定义圆柱面半径,并已 为的x,y,z的长度相同 N是周围围点的数量。默认值 为N= 100。 Ø 定义了矩阵圆柱generatix(圆圈)椭圆 表面。其内容以0和1之间的值,并适用于 小学和中学的母线轴。值的defeault Ø =的(长(x),2)。 矩阵X,Y,Z轴确定圆柱面,冲浪
Princess-Dido-story
- 狄多公主圈地的故事 . 为了建设城市,她需要从当地一片森林中的拥有者那里买一些木材,交易条件是这样 的,在有限面积的森林内,散布着一些树木,而不同的树可得到的木材体积也不相同。 狄多需要划出一个圆形区域,区域内的树木皆归她所有,当然,树木分布位置并不规 则。请大家帮助狄多,在树木总数与分布情况,每棵树的可得到的木材体积已知的情况 下,算一下最大可圈出的木材体积是多少。 可以将树木看做平面内的N个点,以点的权值M0,M1,...Mn表示每棵树可出产的木材体 积。圆
Tulun1
- 凸轮轮廓程序: 1#号凸轮:等速运动规律: 推程h=20mm; 回程h=20mm; 凸轮基圆半径r=50mm; 推程运动角φ=150°; 远休止角φ=60°; 回程运动角φ=150°; -Cam profile program: the# 1 cam: constant speed movement of: Push-way h = 20mm return h = 20mm cam base circle radius r = 50mm push th
Tulun2
- 凸轮轮廓计算: 2#号凸轮:等加速等减速运动规律; 推程h=20mm; 回程h=20mm; 凸轮基圆半径r=50mm; 推程运动角φ=180°; 回程运动角φ=180°; -Cam profile calculation: the# 2 cam: the law of such acceleration and deceleration push the process h = 20mm return h = 20mm cam base circle ra
Tulun3
- 凸轮轮廓计算: 3#号凸轮:正弦加速度运动规律 推程h=20mm; 回程h=20mm; 凸轮基圆半径r=50mm; 推程运动角φ=180°; 回程运动角φ=180°; -Cam profile calculation: the# 3 cam: sine acceleration movement of push process h = 20mm return h = 20mm cam base circle radius r = 50mm push the pr
GravityField
- 重力场中,两弹性系数为k的弹簧中间架起一质量为M的托盘,盘静止。托盘质心上h处有一质量为m、半径为r的小球,速度为v(可正可负)。用数值模拟的方法模拟托盘及球的运动-Gravitational field, the two elastic spring coefficient k, the middle set up a mass M of the tray, plate stationary. H at the heart of quality tray has a mass m, radiu
RBNN
- Algorithm based in graph theory, in which form cluster around of a radius r of a point.
example_8_end
- 自行车轮饰物的运动轨迹。路面视为光滑曲线f(x),饰物离车轮中心距离为r,车轮半径为R。-The trajectory of the bicycle wheel accessories. Road surface as a smooth curve f (x), and accessories from wheel center distance r, the wheel radius R
SharifPWE_BZplot
- The ouput is the TE/TM band structure (first five bands) along pricipal directions (G-X-M-G) of a square-lattice photonic crystal with unit cell consisting of a substrate of "epb" relative permittivity with circular rods(holes) of "epa" rel
cPP
- 已知圆半径r=2.5 圆柱高h=4,求圆的周长,面积,圆球体积,圆柱体积,用cin输入要计算的项目,然后输出计算结果,输入输出时要有文字提示-Known radius r = 2.5 cylinder h, = 4, of circular perimeter, area, the sphere volume, cylinder volume, cin input to calculate the project, and then outputs the calculation results
BEM_FOR_MATLAB
- 边界元测量垂直接地极地表电势的MATLAB程序垂直接地极半径r=0.05m,长度l=0.5m,垂直接地极上电位V0=30V,边界元法求解径向向外8个点的电势.-Boundary element potential measuring vertical ground Polar table MATLAB program vertical ground electrode radius r = 0.05m, length l = 0.5m, the vertical grounding on