问题描述： 给定n个石子，其重量分别a1,a2,a3...an,要求将其划分成m份，每一份的划分费 义为这份石了中最大重量与最小重量的差的平方。总划分费用等丁m份划分费用之和。 编程任务 对于给定的n个石子，求一种划分方案，使得总划分费用最小。-Descr iption of the problem: Given n-stones, its weight, respectively a1, a2, a3 ... an, asked that it be divided into m

code to get optical flow using sum of square difference method

包括kf，ekf，pf，upf可以自己定制模型参数，完成滤波-ReBEL currently contains most of the following functional units which can be used for state-, parameter- and joint-estimation: Kalman filter Extended Kalman filter Sigma-Point Kalman filters (SPKF) Unscented

计算了0.001-0.999之间数字的平方和，并给出图形，并与matlab自身的函数power进行了比较，给出了差值的图形-Calculates the square sum of the Numbers between 0.001 0.999, and the graphics is given, and with the function of matlab power are compared, and the difference of the graphics is presented