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非守恒-无激波-跨声速程序
- 非守恒-无激波-跨声速程序
守恒-无激波-跨声
- 守恒-无激波-跨声
maccomack_1d
- 一维Riemann问题，即激波管问题，是一个典型的一维可压缩无黏气体动力学问题，并有 解析解。对它采用二阶精度MacCormack两步差分格式进行数值求解。同时，为了初学者入门和练习方便,这里给出了用Fortran77语言编写的计算一维Riemann问题的计算程序，供大家学习参考。——计算流体力学教程-One-dimensional Riemann problem, that shock tube problem is a typical one-dimensional compressible
lax-wendroff
- 二维Fortran编写的激波在壁面反射程序。采用lax wendroff二阶精度编写-shock reflection on a rigid wall
shockreflect_LW
- Lax-Wendroff格式计算二维斜激波在固壁反射的算例，控制方程为无粘Euler方程-Lax-Wendroff scheme for obique shockwave with Euler equation
1D-Euler
- 用于求解一维气体动力学的欧拉方程代码，采用戈东诺夫格式，显式推进，可仿真非定常激波管-For solving one-dimensional Euler equations of gas dynamics code, using Godunov format, explicit advance, can simulate unsteady shock tube
Shock-Wave-Calculation
- 用CFD方法计算超声速下小攻角翼型产生的激波-CFD method with a small angle of attack under supersonic shock wave generated airfoil
Euler-Riemann
- 一维黎曼激波管问题 NND格式 欧拉方程-One dimension Riemann Shock-wave tube problem . NND scheme Eular Equation
liman
- 一维 问题，即激波管问题，是一个典型的一维可压缩无黏气体动力学问题，并有 解析解。对它采用二阶精度 两步差分格式进行数值求解。-One-dimensional problem, namely shock tube problem is a typical one-dimensional compressible inviscid gas dynamics problems, and analytical solutions. It uses a two-step difference schem
Lax-Webdroff2D
- 斜激波在平面刚壁上反射问题是具有解析解的二维可压缩无黏流动问题。对它采用具有二阶精度 两步差分格式进行数值求解-Oblique shock reflection problem in the plane wall is just a two-dimensional analytical solution of compressible inviscid flow problems. It has a second order accuracy using a two-step numerical
oned_euler_v1
- 一维Euler方程求解，例子是激波管问题。采用了Godunov格式-one dimensional Euler equation solving for shock tube problem
sod
- 计算空气动力学sod激波管压力密度速度计算程序，使用了Van Leer方法、Roe方法做通量分解，WENO格式修正数据。-Pressure, density, velocity of shock tube(sod), calculated by CFD method Van Leer , Roe with format WENO
激波管
- 一维激波管的计算流体力学数值仿真计算，采用MacCormack法(Using MacCormack method to solve the problem of shock nozzle in MATLAB)
激波捕捉C++求解程序
- 此为二维激波捕捉程序。是学习计算流体力学入门必学程序。(This is a two-dimensional shock capture program. It is a necessary program for learning computational fluid dynamics.)