搜索资源列表
maze1
- maze1(USACO) 走迷宫，计算需要的最小步数。经典的Dijkstra算法，初始的图形转化成矩阵是关键。矩阵的维数没有必要等于节点数，可以直接在二维上计算。入口和出口没必要计算。注意fin会忽略空格。预处理的很多东西可以在后面直接做，没有必要在前面专门做。后来发现没有必要计算所有点到两个出口的距离，而可以直接从两个出口开始，计算他们到迷宫中各个格子的最长距离。 算法千辛万苦想出来了，就应该对自己有信心，出现错误了之后有可能是哪里有笔误产生的。尤其是跟踪结果发现有奇怪的地方的时候。
Usaco
- USACO部分试题,可供通过USACO部分题目-USACO part questions, available through USACO section title
USACO
- 美国USACO题库源程序， 美国USACO题库源程序，美国USACO题库源程序-USACO solutions
USACO
- USACO题库以及比赛代码 USACO题库以及比赛代码 USACO题库以及比赛代码 -USACO item bank as well as the game code USACO item bank, as well as game code USACO item bank, as well as the code matches the code USACO item bank, as well as game code USACO item bank, as well as
lphone
- Usaco lphone (09feb) 题解-analysis of lphone
src
- USACO humble problem answer
ride
- The first problem in USACO. USACO 第一章第一题。ride
mixingmilk
- usaco练习题1.3.1，倒牛奶问题，深度搜索，快速排序-usaco exercises 1.3.1, pour the milk problem, the depth of the search, quick sort
calfflac
- USACO练习题1.3.4，回文检测，数据结构-USACO exercises 1.3.4 palindrome detection, data structures
sprime
- USACO 1.5.3 sprime源代码，给同学们点借鉴吧~~考试的时候有的时候只让用iostream库啊有木有-Source code USACO 1.5.3 sprime, to point students learn to exam time and sometimes just let iostream library for wooden have
USACO
- USACO系统第一章节所有源码，自己编写，注释详细-USACO system in the first chapter of all source, their preparation, detailed notes