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Java
- 用多进程同步方法解决生产者——费者问题 设计目的：通过研究Linux 的进程机制和信号量实现生产者消费者问题的并发控制. 说明：有界缓冲区内设有20个存储单元，放入/取出的数据项设定为1-20这20个整型数. 设计要求： (1)每个生产者和消费者对有界缓冲区进行操作后，即时显示有界缓冲区的全部内容，当前指针位置和生产者/消费者县城的标识符. (2)生产者和消费者各有两个以上. (3)多个生产者或多个消费者之间须有共享对缓冲区进行操作的函数代码.
PCProblem
- 多进程同步解决生产者消费者问题 代码+报告+EXE演示文件-Multi-process synchronization code to solve the producer consumer+ report+ EXE demo file
operation-2
- 哲学家就餐问题--操作系统理解pv原语 解决进程间同步问题-operation problem of Dining Philosophers
readandwriter
- 读者和写者线程进程同步问题，比较详细，读者-写者的读写限制（包括读者优先和写者优先）-Readers and those who write thread synchronization process, more detailed, and readers- to write the read and write restrictions (including the readers who write priority and priority)
ProducerConsumer
- 分析进程的同步与互斥现象，编程实现经典的进程同步问题——生产者消费者问题的java模拟 -Producer and Consumer
Sleeping-
- 操作系统经典进程同步问题--理发师睡觉问题-Classic operating system process synchronization problems- problems sleeping barber
two-thread
- java双进程同步互斥的问题，一个文件写一个文件播放，播放完成后，删除这个文件，去读另外一个文件，于此同时写这个文件。-java mutually exclusive two-process synchronization problem, a file write a file to play, play is complete, delete this file, to read another file, this also write to this file.
java
- 实现哲学家进餐问题，一共有五位哲学家在思考或者进餐，解决进程同步的问题-Dining philosophers problem to achieve
ProducerCustomer
- 用JAVA实现生产者消费者问题。生产者-消费者问题是一个经典的进程同步问题-Producers and consumers to achieve with JAVA. Producer consumer problem is a classical process synchronization problem
processsynchronous
- 经典胡睡觉理发师问题，利用信号量实现进程同步-Classic Hu sleeping barber problem using semaphores to achieve process synchronization