搜索资源列表
BM
- The Berlekamp-Massey algorithm is an efficient algorithm for determining the linear complexity of a finite binary sequence sn of length n. The algorithm takes n iterations, with the Nth iteration computing the linear complexity of the subsequence sN
Theory of a multimode semiconductor laser with optical feedback
- We discuss the derivation of multimode rate equations for the descr iption of a semiconductor laser with external cavity. We adopt a formulation where the complex field amplitudes are coupled to the nonlinear gains. For N lasing modes, this leads t
duoxiangshi
- 多项式相乘一元稀疏多项式简单计算器的基本功能是： （1)输入并建立多项式； （2）输出多项式，输出形式为整数序列：n,c1,e1,c2,e2,...,cn,en,其中n是多项式的项数，ci和ei分别是第i项的系数和指数，序列按指数降序排列。 （3）多项式a与多项式b相乘，建立多项式。 -Sparse polynomial multiplication unary polynomial basic functions of the calculator is simple:
jinsishang
- 给出了通过序列求近似熵的程序，其中N表示序列的长度-Sequence is given by the approximate entropy of the process, where N denotes the length of the sequence
Cd4093中文资料
- Cd4093由四个2输入端施密特触发器电路组成。每个电路均为在两输入端具有斯密特触发功能的2输入与非门。每个门在信号的上升和下降沿的不同点开、关。上升电压(V P)T和下降电压(V N)之差定义为滞后电压
QualNet4.nChineseTutorial
- 仿真平台QualNet（4.n版本）中文教程-Simulation platform QualNet (4.n version) Chinese Tutorial
rk4
- 龙哥库塔4阶函数的计算，也可以改改变成3，2，n阶的。-龙哥Kutta 4th order function calculation can also be changed into 3,2, n bands.
GameScheduling
- 在一个田径运动会上，已知有m个选手参加比赛，运动项目共有n个，这包括若干个诸如100m之类的以个人形式参加的单项和4×100m之类的多人参加的集体项目。另外，每位选手最多可参加3个单项，集体项目则不限制。为使选手能正常比赛，需要对赛程作合理安排。请构造出有关模型和数据结构，设计出合理安排赛程的算法和程序，以使每位选手都能正常地参加比赛，并要求比赛时间尽可能短-In a Track and Field Games, a player known to have m race, sports a t
josepRing
- joseph环。任务：编号是1，2，……，n的n个人按照顺时针方向围坐一圈，每个人只有一个密码（正整数）。一开始任选一个正整数作为报数上限值m，从第一个人开始顺时针方向自1开始顺序报数，报到m时停止报数。报m的人出列，将他的密码作为新的m值，从他在顺时针方向的下一个人开始重新从1开始报数，如此下去，直到所有人全部出列为止-joseph ring. Tasks: number is 1,2, ... ..., n of the n individuals in accordance with th
asta
- 如果想深挖ASTA的潜力必须得去看源代码 如果只是普通应用 其实不需要完全了解全部控件的用法 就那几个 已经够用了-If you want to root out the potential of ASTA have to look at the source code if the application is only a matter of fact the general is fully aware of all the controls do not need to use on
ATM-N
- ATM教学要求，银行网络系统分析，功能介绍-ATM teaching requirements, banking network systems analysis, functional introduced
in_LPF2
- 输入数据,产生的sin信号,其中含有噪声数据,可用于S/N的计算-Input data, generated by sin signal, which contains noise data can be used for S/N calculation
make_linux_rootfs
- 介绍了嵌入式linux根文件系统的制作，报考ramdisk，cramfs,yaffs,以及nfs的配置-Introduced the embedded linux root file system of production, applying ramdisk, cramfs, yaffs, as well as the configuration of nfs
Class-based_n-gram_models_of_natural_language
- We address the problem of predicting a word from previous words in a sample of text. In particular, we discuss n-gram models based on classes of words. We also discuss several statistical algorithms for assigning words to classes based on the fre
yuhen
- 用贪心算法解题: 设n是一个正整数。现在要求将n分解为若干互不相同的自然数的和，且使这些自然数 的乘积最大。-Greedy algorithm with problem-solving: Let n be a positive integer. N decomposition will now require a number of separate and natural number, and make them the product of the largest natural nu
GaussIterativeMethod
- （1） 编制解n阶线性代数方程组AX=b列主元三角分解法的通用程序. （2） 用所编的程序解线性方程组.给出解向量,保留5位有效数. -(1) the preparation of solution of n-order linear algebraic equations AX = b out PCA generic triangular decomposition process. (2) the procedures used by the series solution of l
2006111099
- 编写用回溯法求n后问题的通用函数；其中n值为输入,为任意的输入。 -Retrospective method used to prepare after the issue of n generic function which n value of input, for arbitrary input.
njiec
- 计算N！： 编写计算N阶乘的程序，数值N由键盘输入，N的值要在0到65536之间（用一个16位的字表示），结果在显示器上显示。 -Calculation of N! : Preparation of N factorial calculation procedures, numerical N from keyboard input, N the value of 0-65536 in between (with a 16-bit words expressed), the result
findmoney
- 10. 设有n种不同面值的硬币，各硬币的面值存在于数足T[n]中。现要用这些面值的硬币来找钱。可以使用的各种面值的硬币个数存于数组Coins[n]中。对任意钱数0<=m<=20009，设计一个用最少硬币找钱m的方法。-10. There are n different denominations of coins, each coin with a face value exists in the number of adequate T [n] Medium. Is to use
protocolo_modbus_2
- La designaci贸n Modbus Modicon corresponde a una marca registrada por Gould Inc. Como en tantos otros casos, la designaci贸n no corresponde propiamente al est谩ndar de red, incluyendo todos los aspectos desde el nivel f铆sico hasta el de aplicaci贸n,