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example1
- 题目:有1、2、3、4个数字,能组成多少个互不相同且无重复数字的三位数?都是多少? 1.程序分析:可填在百位、十位、个位的数字都是1、2、3、4。组成所有的排列后再去-Title: 1, 2, 3, 4 digital, can be composed of a number different from each other and no duplicate numbers three digits? Are how many? Program analysis: can be fille
example28
- 题目:有5个人坐在一起,问第五个人多少岁?他说比第4个人大2岁。问第4个人岁数,他说比第 3个人大2岁。问第三个人,又说比第2人大两岁。问第2个人,说比第一个人大两岁。最后 问第一个人,他说是10岁。请问第五个人多大?-Title: 5 people sit together, and asked the fifth person how old? He said the 2-year-old than 4 people. Ask individuals age 4, he
EPM2428V120327
- EPM2428 is a new product belonging to RFIC’s EPM family. It’s a three-stage power amplifier with super high output power in 2.4-2.5GHz band utilizing InGaP/GaAs HBT process. With excellent linearity performance, the device delivers 28dBm
TW2851-datesheet
- TW2851 数据手册 4 通道 音频 视频解码 编码器-tw2851 datasheet techwell 4 Channel A/V Decoder with Multiplexer/VGA/ LCD Display Processor for Security Applications
pratica-(4).rar
- Pratica de laboratório de telecomunicaç õ es,Pratica de laboratório de telecomunicaç õ es
Business-Economics-a-Finance-w
- How to Use This Book 1 2 Mathematical and Simulation Models in Business Economics 16 3 MATLAB and Simulink Design Guidelines 26 4 Importing and Reporting Your Data 53 5 Library Functions for
AD7799PDF
- AD7799/AD7798 特性: RMS 噪声(有效值噪声): 在 4.13HZ 转换率下紧为 27nV(AD7799). 在 16.7HZ 转换率下为 65Nv. · 低 功 耗 ,典型为 300uA · 内 置 1 一 128 增益的低噪声可编程仪表放大器 · 内 置 时 钟振荡器,省去了外接晶振 · 低 非 线 性度:0.0015 · 内 设 自 校准电路 · 带 有 SPI 数据接口,可以方便地与 DPS 或者 MCU 连接 · 50 H
viLib
- nice c++ using opencv2.4.4 and vc++10-nice c++ using opencv2.4.4 and vc++10
15-04-0218-01-004a-ieee802-15-4-mac-overview
- THE IMPLENTATION OF THE MAC PROTOCOL USING THE FPGA ALTERA 3
tepe3no1
- Why your files are not be used? 1.The content is too simple 2.Is not a sourcecode or document 3.lost some files 4.Descr iption is not detailed or not correct 5.Compressed file has password 6.Sourcecode duplicate or already exist
wangluogaishu
- 第一章网络概述 谢希仁 1.1 计算机网络的形成和发展 1.2计算机网络的拓扑结构 1.3 计算机网络的分类 1.4 计算机网络的组成 1.5计算机网络的主要技术指标-The first chapter Outlines of networek. 1.1The formation and development of computer network 1.2Computer network topology 1.3The classification of the
Digital-beam-forming
- 画出下述情况下均匀线阵方向图 1)计算来波方向为0度方向图 2)画出来波方向为45度时的方向图 3)画出来波方向为0度,幅度取分贝数:20log***(单位为dB)时的方向图 4)画出来波方向为0度,随着阵元数的增加,当N=16,N=32时的方向图,并对方向图的变化情况进行说明-Draw the following conditions uniform linear array 1) calculation of wave direction is 0 degrees
u4
- 有一个4×4的键盘,按下一个键,LED上显示相应的键值(0~F),并且喇叭响一声-A 44 keyboard, press a key on the LED display the corresponding key (0 to F), and the horn sounds
AD7991_7995_7999
- AD7991_7995_7999转换器说明-4-Channel, 12-/10-/8-Bit ADC with I2C-Compatible Interface in 8-Lead SOT-23
adc_dma
- 无按键按下,4行输入IO,均为高电平(因为有外部上拉电阻) 3、若按键按下,对应行IO被拉低(假设为第X行),检测为低电平。按键所在行(X行),被鉴别出来。 4、此时,依次改变4列的输出为高,当遇到按键所-DSP28335 ADC
iBooty
- Why your files are not be used? 1.The content is too simple 2.Is not a sourcecode or document 3.lost some files 4.Descr iption is not detailed or not correct 5.Compressed file has password 6.Sourcecode duplicate or already exist
wpan_zbr
- 820.15.4的NS2仿真tcl脚本,就这些吧-820.15.4 The NS2 simulation tcl scr ipt, these bars
fat
- 硬盘以及FAT文件系统介绍 1)硬盘物理结构 2)硬盘逻辑结构 3)磁盘引导原理 4)FAT分区原理-The introduction of fat
1
- 八皇后问题是求出在一个n×n的棋盘上,放置n个不能互相捕捉的国际象棋“皇后”的所有布局(皇后可以沿着纵横和两条斜线4个方向相互捕捉)的问题。是一种比较常见的练习C语言递归或者栈使用的程序问题。-Eight queens problem is to find an nn chessboard, place of n are not mutually capture chess " queen" of all the layout (Queens and two along the
b3-1.4.1
- ai vai o trericeor lixo para voces seus bostasas