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fuzzypid
- 模糊C程序 模型为一阶内有模糊规则 用于电阻炉温度控制 -Fuzzy C for one process model has fuzzy rules in order for the resistance furnace temperature control
C++
- 编写一个程序，在屏幕上出现一个圆心沿正弦曲线轨迹移动的实心圆，要求每隔4分之一周期，圆的填充色和圆的周边颜色都发生变化（颜色自己选取），同时圆的半径在四分之一周期内由正弦曲线幅值的0.2倍至0.6倍的线性增长。-The preparation of a procedure on the screen there is a center of a circle along the sinusoid trajectory mobile solid round, one request every 4
Cbaodian
- C语言编程宝典之一，不可多得的葵花宝典是也，-C programming language, one book, a rare book of sunflower is also, huh, huh
wdt
- 汇编和C语言两种方法的看门狗演示程序 在16383个机器周期内必须至少喂狗一次。激活看门狗后,喂狗,P0.7、P0.6引脚上的LED闪烁发光。激活看门狗后,如果不喂狗,则复位 P0.1、P0.0引脚上的LED闪烁发光-Compilation of the two methods and C language demo of the watchdog 16,383 machines in the cycle must have at least one喂狗. Watchdog activated
12
- 该文件是一个用于学习和交流的东西，有助于c程学习者-This file is one for learning and sharing things, helping learners c Cheng
c_c_plus_plus_mianshiti
- 本人整理的c，c++面试笔试题，面试笔试必备，是从网上诸多面试笔试中选取合并整理的，看这一个，基本上就可以解决面试笔试中能遇到的常见问题了。-I am finishing c, c++ Interview Questions pen, interview necessary written, is written from the Internet, select a number of interviews consolidate the ways of looking at this one
1
- 利用c语言编写的最速下降法程序，其中包括利用进退法和0.618法进行的一维搜索-Using c language of the steepest descent procedure, including the advance and retreat method and 0.618 using one-dimensional search method
CLauguage
- 讲述C语言 精彩编程百例。对C语言的学习有帮助。-About one hundred cases of C programming language exciting. On the C language learning help.
fractal-use
- 分形的练习一 ①Koch曲线 用复数的方法来迭代Koch曲线 clear i 防止i被重新赋值 A=[0 1] 初始A是连接（0，0）与（1，0）的线段 t=exp(i*pi/3) n=2 n是迭代次数 for j=0:n A=A/3 a=ones(1,2*4^j) A=[A (t*A+a/3) (A/t+(1/2+sqrt(3)/6*i)*a) A+2/3*a] end plot(real(A),imag(A)) axis([0 1 -
Thinking-in-CPP
- Think in C++, help the one to learn C++ faster.
1
- 对虚函数进行啦详细的讲解，对于初学者来说是很好的学习资料-It is very import for a new one who want to study C++.
cpp_high-quality-programming
- 请花一两个小时认真阅读这本百页经书，你将会获益匪浅，这是前面 N-1 个读者的 建议。C/C++编码高效指南- Please take twelve hours one hundred carefully read this book, you will be benefited, which is in front of the N-1 reader Recommendations. C/C++ coding efficiency guidelines
N-S-equation
- 一维可压 ns方程 数值求解，c语言 fortran语言源程序，是学习cfd的入门实例。-One-dimensional compressible numerical equation solver ns, c language fortran language source code, is to learn cfd entry instance.
one-dimension-Riemann-
- 一维 Riemann问题，Riemann问题的物理模型及数值求解源程序，c fortran 语言，是学习cfd的入门实例。-One-dimensional Riemann problem, physical models and numerical problem solving Riemann source, c fortran language learning cfd' s entry instance.
BNUTBDJNBOOFR
- 【程序29】 题目：给一个不多于5位的正整数，要求：一、求它是几位数，二、逆序打印出各位数字。 1. 程序分析：学会分解出每一位数，如下解释：(这里是一种简单的算法，师专数002班赵鑫提供) 2.程序源代码： 复制代码 代码如下: #include stdio.h #include conio.h main( ) { long a,b,c,d,e,x scanf( ld ,&x) a=x/10000 分解出万位 b=x 10000