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计算两个字符串的最长公共子字符串的长度，使用动态规划。-Calculation of two of the longest common sub-string length of string, the use of dynamic programming.
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最长子序列,英文版,电子书 ACM文章1977+Algorithms+for+the+Longest+Common+Subsequence+Problem-The longest sequence, in English, e-books ACM article 1977+ Algorithms+ For+ The+ Longest+ Common+ Subsequence+ Problem
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Longest Common Subsequence Problem. Solution both Iterative and Recursive.
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Constrained LCS. Given two sequences X, Y and a constrained sequence P, a sequence Z is a constrained longest common subsequence for X and Y with respect to P if Z is the longest subsequence of X and Y such that P is a subsequence of Z.
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利用动态规划法求解次最长公共子序列问题。-The use of dynamic programming method for solving second longest common subsequence problem.
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lcs 求出全部的最长公共子序列,实验程序全部采用Java实现，编译器为J2SE SDK 1.5.0_06，集成环境为Eclipse 3.1.2。-lcs find all of the longest common subsequence, experimental procedure used in all Java implementation, the compiler for the J2SE SDK 1.5.0_06, an integrated environment for Ec
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Parallel Algorithms for the Longest Common Subsequence Problem
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在C++环境下开发的最长公共子序列算法，可以下下来试试看-In C++ development environment, the longest common subsequence algorithm can try the next down
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求出所有最长公共子序列（连续序列）
输入：
malose malmose
输出：
lcs_length=3
lcs_string=ose
lcs_string=mal-ouput all the longest common subsequences. the subsequence must be series.
for example:
[input]
malose malmose
[output]
lcs_length=3
lcs_stri
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这是用c 写的关于最长公共子序列的一个算法，是学习算法分析与设计时做的一个实验，希望对初学者有用呵（原来的名字是“最长公共子序列”，因为上传的原因改成现在的名字）-This is c written about one of the longest common subsequence algorithm, learning algorithm is to do analysis and design an experiment, I hope useful for beginners O (t
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算法设计类源码。使用动态规划的方式计算两个字符串的最大公共子序列。-Algorithm design class source code. Calculated using dynamic programming the two most common subsequence string.
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这是算法设计与分析课程实验，动态规划的源程序。包含最长上升子序列，最长公共子序列，最大字段和问题，DP背包问题-This is a test algorithm design and analysis programs, dynamic programming source code. Rising sequence containing the longest, longest common subsequence, maximum field and problems, DP knapsac
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最长公共子序列递归算法，最长限制是10000字符-Longest common subsequence of a recursive algorithm, the maximum limit is 10,000 characters
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本代码是算法设计中的最长公共子序列问题，通过C++编写。-This code is the longest common subsequence algorithm design, written by C++.
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运用动态规划思想和策略，解决最长公共子序列问题。-The use of dynamic programming ideas and strategies to solve the longest common subsequence problem.
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最长公共子序列问题 第一步 最优子结构: 第二步：建立递归式 第三步：计算最优值 -The longest common subsequence problem
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poj 1458
A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..., xm > another sequence Z = < z1, z2, ..., zk > is a subsequence of X if there exists a stri
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本代码实现了算法导论书中最长公共子序列算法。-The longest common subsequence
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VC++实现最长公共子序列的查找定位，简单易懂-The longest common subsequence
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用动态规划思想设计实现最长公共子序列问题，用贪心思想设计实现活动安排问题，并且用不同数据量进行对比分析。(We use dynamic programming theory to design the longest common subsequence problem. We use greedy thought to design the activity scheduling problem, and compare it with different data volume.)
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