资源列表
mazemm
- 用栈实现迷宫算法，四个方向寻求出路，四周加边，寻求路径-with Stack achieve maze algorithm, four direction to seek a way out, surrounded bordered seek path
yuesefu1
- new_code( ) 操作结果：构造空链表，若成功就初始化每个人的相关信息 delete_code( ) 初始条件：线性链表存在 操作结果：释放指向出列的人的结点，并重新报数 -new_code () : List structure space, If successful on each of the initialization information delete_code () initial conditions : There linear chain
bank
- 实现系统多进程管理的银行家算法，合理的避免了进程因为竞争同一资源而出现的死锁问题 -bankbankbankbankbankbankbankbankbankbankbankbankbank
COMPARE
- 用于简单比较两个类似的文本文件，显示不同的地方。-For the simple comparison of two similar text files, display a different place.
vc
- vc代码，用于添回快捷菜单 绘制一个白色矩形背景 可点击任意位置移动的窗体. -vc code for Tim back to the shortcut menu, draw a white rectangle background can click anywhere on the mobile form.
DateTimeExtensionMethods
- DateTime Extension Methods for Visual Studio .NET 3.5 Developers
TestPC
- 用多线程解决生产者消费者问题，每当生产者生产物品，存入仓库，消费者从仓库消费，当仓库满时候，停止生产，仓库为空时，消费者停止消费-Producers and consumers with multiple threads to solve the problem, when producers produce goods into the warehouse, consumer spending from the warehouse when the warehouse is full time
code-p-value-csharp
- z distribution in Csharp
DSW
- P10 （P0）与J12 JP9(P3)与JP5 用8PIN排线连接,P3.2和P3.3外部中断输入 由两个四位数码管分别显示计数-P10 (P0) and J12 JP9 (P3) and JP5 cable to connect with 8PIN, P3.2 and P3.3 external interrupt input consists of two four digital tube display counts
iframe
- ifr a me互相调用，左边一个，右边一个，完整实现了。-ifr a me invoke each other,left one invoke right one,right one invloke left
11
- 这个是基于c语言的视频学习代码，很不错的，值得学习一下-This is based on the c language video learning code, very good, it is worth learning about
chepaijiaozheng
- randon 变换进行车牌矫正，通过randon变换获取倾斜角度，根据倾斜角度进行倾斜矫正。-Radon transformation for license plate correction, through the radon transformation to obtain the tilt angle, according to the tilt angle tilt correction.