资源列表
HTML
- HTML新手比较适用的帮助文档,可以试试(HTML novice more applicable help documents, can try)
no6
- STK satellite trajectory simulation
getstart
- MATLAB官方入门手册 包含一些基本的数据类型,函数,画图方法 matlab getstartThe software described in this document is furnished under a license agreement. The software may be used or copied only under the terms of the license agreement. No part of this manual may be photoco
生产者消费者作业02
- C#编写的有关操作系统中生产者与消费者问题的实例,画面美观,生动形象的描绘了生产者与消费者之间的关系,代码部分简介易懂。(C# is an example of the problem of producers and consumers in the operation system. The picture is beautiful, vividly depicting the relationship between producers and consumers, and the cod
GeoSOS-FLUS Manual_CHS.pdf
- FLUS model for land use prediction manual in Chinese
RunDllVS2015源码
- RunDllVS2015源码 可自己编译!*源码可以自己编译(RunDllVS2015 source code Can be compiled by yourself! You can compile free source code)
hid 源码
- 自动截取通过hid处理的加密狗数据,劫持工具重写源码(read the data of usb dog)
3-7汽车加油
- 该问题采用的是动态规划的思想来解题,用备忘录的方法进行递归,递归的式子后面写出,不能直接以汽车行驶的费用为目标来进行动态规划,因为最优子结构性质得不到证明。所以必须把油量和费用一起考虑,作为动态规划的对象,此时就有了最优子结构性质。(The problem is used in the theory of dynamic programming to solve problems, using recursive method to write memos, recursive formula
24712588
- 易语言POST注册QQ源码,很不错的易语言源码,适合易语言爱好者学习,()
bianyuangaijinquanjuyuzhi
- 图像阈值分割,由传统阈值分割改进的,基于边缘特征的改进算法(Image threshold segmentation)
背包
- 给定n种物品和一背包。物品i的重量是wi,体积是bi,其价值为vi,背包的容量为c,容积为d。问应如何选择装入背包中的物品,使得装入背包中物品的总价值最大?在选择装入背包的物品时,对每种物品i只有两种选择,即装入背包或者不装入背包。不能将物品i装入背包多次,也不能只装入部分的物品i。试设计一个解此问题的动态规划算法,并分析算法的计算复杂性。(Given n items and a knapsack. The weight of the item I is wi, the volume is Bi
3-15样本采集
- 设两次行走等长距离,到达(x1,y1)和(x2,y2)处取得的最大价值为h[x1][y1][x2][y2]。容易证明其具有最优子结构性质。动态规划算法如下。(The maximum value of reaching (x1, Y1) and (X2, Y2) at the same length of two times is h[x1][y1][x2][y2]. It is easy to prove that it has the optimal)