资源列表
Aufgabe1
- Solution for the task in Operating Systems at University Magdeburg 2009 It contains the classes cgastream, cgascreen, stringbuffer, ostream.
e-book
- Windows Server 2008 training kits 70-640 70-642 70-643 70-646 70-647
vlcplayer
- VLC Player Source Code
cal
- 一个简单的有声计数器。在实现了简单的加减乘除的基础上，还增加了三角函数、对数、倒数等功能-A simple sound counter. In the realization of a simple addition and subtraction on the basis of multiplication and division, but also increased the trigonometric, logarithmic, reciprocal and other function
TUT01.03.PVN.NOHB.100106
- A Step-by-step Tutorial about communicating through RS232 in Vietnamese, including VC++6 source code. File format: PDF.
CString
- 常用字符串转换函数个人收集对初学者有很大的帮助欢迎下载-String conversion functions commonly used in personal collection of great help for beginners are welcome to download
filesort
- 实现一个文本文件的内容倒序显示 用VC++编的一个不错的小功能-achieve a text file content using VC reverse shows a good part of a small function
vc_case_100
- 《Visual C++ 6.0 时尚编程百例》100个例子的源代码 非常适合初学者学习-" Visual C++ 6.0 Programming hundred cases of fashion," 100 examples of the source code is very suitable for beginners to learn
fanxushu
- //2.编程序，从键盘输入正整数n，求出n与其反序数之和并输出。例如，输入2038，输出应为 2038+8302=10340。-//2. A program, a positive integer from the keyboard input n, calculate the number of n and its reverse order and output. For example, input 2038, output should be 2038+8302 = 10340.
qishixunyou
- 2. 编程序，使用如下所谓的简单变量“数据平移”方法来求出Fibonacci数列的第n项（的具体项值） 并显示在屏幕上（正整数n通过键盘输入）：说明变量old1=1，old2=1，newItem；新的Fibonacci项newItem总是“距它最近”的前两项（old1与old2）的累加和。而后通过“old1=old2 old2=newItem ”进行所谓的“数据平移”。接着计算另一个新的Fibonacci项newItem，依次循环，直到求出数列的第n项时为止。 -2. A program
tongxunlu
- 通讯录系统的设计与实现，可以实现添加删除查询修改等功能，很全，而且易懂，不错的哦-Address book system design and implementation of query modification can add and delete functions, it is full, and easy to understand, oh well