资源列表
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- 自升级PB 自升级PB 自升级PB-自升级PB
Cprogramming
- C、C++编程经验之谈，很有用，让你改掉不良编程习惯，指导你如何成为程序写作规范的高手。-C, C++ programming from experience, is useful so that you Gaidiao bad programming habits, program guides you how to become a master of writing specifications.
shopping
- 实现购物车功能的实例,非常详细，可运行调试-shopping test
httppost_code
- 上傳網頁功能，包含post/get等-Upload web page features, including post/get, etc. .....................
LSP_Understanding
- this a very good document which describes Layered Service Provider architecture and relavant issue while implementing it.-this is a very good document which describes Layered Service Provider architecture and relavant issue while implementing it.
1445
- 这是用VC++编写的一个活期储蓄程序，很简单，不是很复杂-It is written in VC++ a demand savings program, is very simple, not very complicated
vcshow
- 图形特效显示，包括扫描显示，移动显示，马赛克显示等-Graphic effects shows, including scans showed that mobile display, mosaic displays
UARComponents
- ejercicio 2 de icarnegie ssd4 es el desarrollo de una interface de visua basic, que despiega las opciones segun se ponga numero o string
migong
- 求两点路径是一个数据结构上的典型的迷宫问题，很多数据结构的书上都有介绍，解决办法如下：从一点开始出发，向四个方向查找，每走一步，把走过的点的值+1(即本节点值+1)，防止重复行走，并把走过的点压入堆栈(表示路径)，如果遇到墙、或者已走过的点则不能前进…… -Seeking two path is a data structure of a typical maze, a lot of books on data structures are introduced, the solution is
DeuceNumber
- 把一堆数平均分成N份，保证每一份的和接近于所有数之和除以N，不要求平分以后的每份数据个数相等。这是有现实的程序设计需求的，当时是3份。首先想到要先进行排序，再依次从已排序的数列中抽取，如何进行抽取方法有很多 -The average number of the pile is divided into N copies, make sure that each and close to all the number one divided by N, does not require sp
ExpressionTest
- 中缀表达式转后缀表达式基本思路是：用一个链表 List 储存将要生成的后缀表达式；用一个栈 Stack 储存操作符；判断当前节点， 如果是操作数， 直接加入后缀表达式中， 如果是操作符，则比较前一个操作符和当前操作符的优先级…… -Infix expression basic idea is to switch to postfix expression: list List with a store that will be generated by postfix expression
Vzip-Winmain
- this file is zip source file ( vzip.h/ vzip.c ) the file create zip file to file not folder