资源列表
vcmessage
- Visual C++打造Windows信使服务程序-create Windows Messenger Service Program
HideProcess
- HideProcess.h 直接调用HideProcess（） 就ok
LUA-VC6.0-VCPP
- 在VC++6.0中使用Lua脚本的方法。包括如何设置以通过编译和一些示例资料-In VC++6.0 using Lua scr ipts. Including how to configure VC++ to successfully pass the compiler and some examples
GetHDinfo
- 能获取硬盘序列号等信息的VB6.0源码，请阅读TXT文档内的说明-To obtain information such as hard drive serial number of VB6.0 source code, please read the TXT file with descr iption of
wwee
- 一款MP3播放器源代码，C语言编写，内容丰富，条理清晰-A MP3 Player source code, C language, rich in content, lucid -A MP3 player source code, C language, rich in content, the clarity-A MP3 Player source code, C language, rich in content, lucid
ldap_compare
- 对比ldap的条目，输入ldap条目及相应条件即可获得对比-Compare ldap entries, enter the ldap entries and the corresponding conditions was compared
Information.behalf.EDM.trigonometric.leveling
- 电磁波测距三角高程代资料Information on behalf of EDM trigonometric leveling -Information on behalf of EDM trigonometric leveling
imagedealing
- 我相信很多人都会在GDI图形绘制的头文件，这是现成头文件和实现代码-i believe many people will want to the head in the GDI graphics file, which is ready-made header and implementation code
include
- 从键盘上任意输入3 个整数x、y、z，并按从大到小的顺序显示出来，请编写该程序。要求：输入时x、y、z三个变量中的数是无序的，通过程序处理后，x是最大值，y是次大值，z是最小值。-Any input from the keyboard three integers x, y, z, and press in descending order, write the program. Requirements: The number in the three variables x, y, and
DragDrop
- 拖拽功能源码,可直接应用于将实现拖拽文件、文件夹等的处理，-Drag and drop source code, can be directly applied to achieve drag and drop files, folders and other processing,
RING0
- 强删文件RING0代码，驱动强制删除文件-Delete files RING0 code, driving force to delete files