资源列表
cs-game
- 吃数游戏,宫殿中找出几个数之和是9的数并把它们吃掉,学习Ｃ＋＋的经典程序
poj
- 五个题的源码，poj2745，2746，2750，2764，2765，具体题目见北大poj网站-Five of the source title, poj2745, 2746,2750,2764,2765, specific topics see North POJ website
uhuffmd
- SEGA游戏图像解压程序，用HAFF解压-SEGA image decompression procedures
zifuchau
- 字符串操作，对于字符串得基本操作得源代码，简单易懂-String operations, for the basic operation of the string must have the source code, easy to understand
wekafenleiqi
- weka分类器，用weka分类器做分类，可以用做其他算法的基分类器。分类效果很好-classify with weka classifier.it can be used as based classifier for other algorithms. it works well
Eight_Signals_CFT
- 数字信号处理中教学用的的几个常用的波形，dft变换-Several commonly used in digital signal processing waveform of teaching, dft conversion
optimiztion
- 一个基于伪谱法解决航天器轨迹优化问题的小程序实例。-This is a program of the spacecraft trajectory optimization based on pseudo-spectral method.
weixin
- dedecms Micro-channel cloud housekeeper (for dedecms) of a micro-channel support plug-ins-Micro-channel cloud housekeeper (for dedecms) of a micro-channel support plug-ins
canon
- 源程序使用matlab编写 经过运行后 可以产生卡农音乐-it can produce canon music
Joseph_Circle
- 约瑟夫问题如下：已知n个人(n>=1)围桌一园桌周围，从1开始顺序编号。从序号为1的人开始报数，顺时针 数到m的那个人出列。他的下一个人又从1开始报数，数到m的那个人又出列。依此规则重复下去，直到所有人 全部出列。求解最后一个出列的人的编号!-Joseph problem as follows: Given n people (n> = 1) sit around a park around the table, in order a start number. From
csp
- 脑机接口中运动想象，经典算法共空间模式CSP-common spacial pattern
main2
- C++设计模式中，工厂模式的源码，代码简洁有注释，非常适合初学者。-C++ design mode, the factory model source code concise notes, very suitable for beginners.