资源列表
24
- 题目24：设计一个程序。 先接受一个字符串，然后显示其中数字符的个数、英文字母的个数和字符串的长度； 抽去其中的空格，按相反的顺序显示这个改变后的字符串； 用户输入第二个字符串，显示的时候全都以*出现，然后判断用户输入的字符串是否与刚才处理后的字符创是否相同，若相同，输出“Password Right!”，否则输出 “Password Error!”。
CBaseSocket
- Windows socket网络编程，自己封装的一个类，大家可以-windows socket base
normalization_pic
- 圖像縮放源碼,程式初學者可應用,初學者可以此進行修改,请參考-Image scaling source, the program can be used for beginners, beginner could be modified, please refer to
Rearth-answero
- 旋转地球，很爽的，自学的好资料，，非常难得-earth可直接使用。 -The rotating earth, cool, self-information, and very rare-earth can be used directly.
yiqunsuanfa
- 蚁群算法的matlab代码，对于数学建模非常有用。-Ant colony algorithm matlab code, very useful for mathematical modeling.
menu
- This is a javascr ipt code for menu control.. Menu navigation is done by this source code.. enjoy it.. it is good..
chengxu
- 数据的高级整理，数据分析、数据表格化和图形化输出口-The advanced sorting of the data, data analysis, data tables and graphical output
amam_ampm
- 功放非线性仿真，输入为BPSK信号,功放模型为volterra-Amplifier nonlinear simulation, the input signal is BPSK
KaCheGenxingProblem
- 卡车跟新问题，这是动态规划的一个典型的例题-A typical example of a problem with the new truck, which is dynamic programming
EjemploDisplay
- VHDL code for a 7-Segment display.
AttenuationRelationship
- Near-Source Ground-Motion (Attenuation) Relations for the Horizontal Component of Peak Ground Acceleration
format
- 费马小定理（包含生成随机数） 不足是大数测试不通过-Fermat s little theorem (including generating random numbers) Testing is not through lack of Tarsus