资源列表
mazemm
- 用栈实现迷宫算法，四个方向寻求出路，四周加边，寻求路径-with Stack achieve maze algorithm, four direction to seek a way out, surrounded bordered seek path
yuesefu1
- new_code( ) 操作结果：构造空链表，若成功就初始化每个人的相关信息 delete_code( ) 初始条件：线性链表存在 操作结果：释放指向出列的人的结点，并重新报数 -new_code () : List structure space, If successful on each of the initialization information delete_code () initial conditions : There linear chain
vc
- vc代码，用于添回快捷菜单 绘制一个白色矩形背景 可点击任意位置移动的窗体. -vc code for Tim back to the shortcut menu, draw a white rectangle background can click anywhere on the mobile form.
DateTimeExtensionMethods
- DateTime Extension Methods for Visual Studio .NET 3.5 Developers
code-p-value-csharp
- z distribution in Csharp
f8-USER-composite-hashin
- dyna subroutine example composite
Binary-decimal-conversion
- 十进制转换二进制 C++实现 仅供参考 -Binary decimal conversion
DSW
- P10 （P0）与J12 JP9(P3)与JP5 用8PIN排线连接,P3.2和P3.3外部中断输入 由两个四位数码管分别显示计数-P10 (P0) and J12 JP9 (P3) and JP5 cable to connect with 8PIN, P3.2 and P3.3 external interrupt input consists of two four digital tube display counts
Time-class
- 增强的Time类，在原有基础上时Time对象中的时间递增一秒:递增到下一分钟,递增到下一小时,递增到下一天. -Enhanced Time class, based on the original Time when the object is incremented second time: increments to the next minute, the next hour increments, increments to the next day.
11
- 这个是基于c语言的视频学习代码，很不错的，值得学习一下-This is based on the c language video learning code, very good, it is worth learning about
overloading
- 此代码实现的是C++中的简单的运算符重载问题。-This code is C++ The simple problem of operator overloading.
chepaijiaozheng
- randon 变换进行车牌矫正，通过randon变换获取倾斜角度，根据倾斜角度进行倾斜矫正。-Radon transformation for license plate correction, through the radon transformation to obtain the tilt angle, according to the tilt angle tilt correction.