资源列表
fet110_1
- msp430一个C语言的看门狗源程序，，请大家多多帮我-Controller of a C-language source watchdog, please help me find a lot
简单的链的倒置（c++）
- 给定一条单向链，设计程序把链倒过来，并输出结果。要求直接在这条链上完成倒置操作，只可增设有限的几个辅助变量。 用栈的方法。
地方
- 这是一个计算数字平台长度的程序，如： 运行时输入： 111122333，结果为: 4 1111 注：本程序在dos中或windows98中运行。-This is a digital platform length calculation procedures, such as : Runtime input : 111122333, the result : 4 1111 Note : This procedure dos or running Windows98.
VB6.0.BO
- Private Sub cmdConnect_Click() If Len(Text1.Text) = 0 And Len(Text2.Text) = 0 Then MsgBox 123.12.25.38 Exit Sub Else If Len(Text1.Text) > 0 Then tcpClient.RemoteHost = Text1.Text Else tcpClient.RemoteHost = Text2.Text End
CAudioRouting
- CAudioRouting AppWizard has created this AudioRouting DLL for you. This file contains a summary of what you will find in each of the files that make up your AudioRouting application. -CAudioRouting AppWizard has created this AudioRoutin
Softwareregisrationprocess
- 根据CPU序列号和磁盘序列号设计软件注册程序-Serial number under the CPU and disk serial number of the registration process design software
Josephus
- 约瑟夫环（Josephus）问题：古代某法官要判决N个犯人的死刑，他有一条荒唐的法律，将犯人站成一个圆圈，从第S个人开始数起，每数到第D个犯人，就拉出来处决，然后再数D个，数到的在处决……知道剩下的最后一个可赦免。-Central Joseph (Josephus) Question: Ancient N a judge to sentence a prisoner to death, he has a ridiculous law, prisoners stand in a circle, S
danpianji
- 单片机的设计文件，使我们用的可以随便下载。实用版本-Single-chip design documents, so that we can be used to download. Practical version of
1
- c#控件随窗口放大而放大，希望能帮助一些写程序不知道控制控件位置的朋友-c# controls with the window zoom zoom friend, hoping to help some of the writing program do not know to control the control position
Split-and-retain-the-delimiter
- Split方法后，保留分隔符 Split方法后，保留分隔符-After the Split method, retaining the delimiter
CONSTANT_Double_info
- The CONSTANT_Long_info and CONSTANT_Double_info represent eight-byte numeric (long and double) constants.< P> .
指针程序
- 一个关于指针的小程序，更多的是学习用法而不是提高，各位高手可以忽略此程序。