资源列表
inv
- 求矩阵逆嘚多种方法，可以任一选择，aaaaaaaaaaaaaa,无解压密抹-De inverse matrix for a variety of methods, can be the head of a choice, aaaaaaaaaaaaaa no secret extract clean
C.case
- c语言基础程序代码,适合初学者,欢迎下载.-c language foundation program code, suitable for beginners, are welcome to download.
I2C-arm
- winavr系列的源程序模拟I2C总线,比较的好-winavr series of simulated source I2C bus, a good comparison
benefits
- An ASPX file for creating benefits page for enterprise.
DoubleLinkList
- 初始化双链表H（H为单链表头指针） 依次采用尾插法插入’a’,’b’,’c’,’d’,’e’五个字符元素 输出双链表H 输出双链表H的长度 判断双链表H是否为空 输出双链表H的第三个元素 输出双链表H中字符元素’d’的位置 在第四个元素位置上插入字符元素’f’ 输出双链表H 删除双链
dancicifa
- 以文本文件形式输入源程序，并对源程序从左到右进行扫描，把构成源程序的字符串拼接成为单词串；并把其转换成属性字输出到文件中。 -A text file input source, and the source code to scan from left to right, to constitute a source word string string splicing and to convert it into a property of word output to a file
sourceControlPressed
- Source Controll Pressed - program-Source Controll Pressed - program
AccessDb
- 这是C#的access连接的类，简化了连接数据库要写的代码-This is the C# class access connection simplifies connecting to the database to write the code
cPP
- 便于学习面向对象c++语言学习的几个例子-Easy to learn object-oriented language learning a few examples c++
gudianwenti
- 题目：古典问题：有一对兔子，从出生后第3个月起每个月都生一对兔子，小兔子长到第三个月 后每个月又生一对兔子，假如兔子都不死，问每个月的兔子总数为多少？
1
- Required method for Designer support - do not modify the contents of this method with the code editor.
cgmotion
- fluent udf的动网格程序，实现了刚体和基于节点的运动-cg-motion grid motion