资源列表
Md5Code
- C编写，实现字符串摘要、文件摘要两个功能。 里面主要包含3个文件: Md5.cpp、Md5.h、Main.cpp。其中Md5.cpp是算法的代码，里的代码大多是从 rfc-1321 里copy过来的；Main.cpp是主程序。 -C prepared, the realization of string summary document containing a summary of two functions. Which mainly includes three documents:
EVC
- EVC高级编程及其应用开发，里面有好多实例，供大家参考，有不足处请多多指教-EVC high-level programming and application development, there are a lot of examples for your information, there are deficiencies in the exhibitions, please
1231312412
- 编译原理中的词法分析,分析程序中的字符和其它符合的识别问题-Compilation Principle of lexical analysis procedures, and other characters in line with the identification of problems
3do
- 航班管理 -Flight management flight management
EllicAntenna11272007
- 微带馈电半椭圆带阻型偶极天线的HFSS模型，相信每个做天线的人都非常喜欢这样的东西的吧~-Microstrip-fed semi-elliptical bandstop-type dipole antenna HFSS model antenna do believe that every person who is very like the right thing to do ~
Kochslot
- 一个较为简单的分形天线的HFSS模型，以此为基础可以构建其他更为复杂的模型-A relatively simple fractal antenna HFSS model as a basis to build other, more complex models
Lesson2Code
- C++经典语法与应用，类的编写与应用，构造与析构函数，函数的重载，类的继承，函数覆盖，基类与派生类的构造函数、析构函数先后调用顺序，如何在派生类构造函数中向基类的构造函数传递参数，this成员变量，类型转换的内幕，虚拟函数与多态性,引用和指针的变量的区别与共同处。VC工程的编译原理与过程，将工程中不同的类拆分到不同的原文件中，每一个类由一个.h和.cpp文件共同完成，头文件重复定义问题的解决，培养了学员良好的编程习惯，也为以后分析MFC Appwizard生成的工程奠定了良好基础。-err
ir
- 透過電腦觀察紅外線和无線波形,有線路圖,自己做-Through the computer to observe the infrared and wireless waveforms, there are circuit diagram, do
librarian
- 简单的学生成绩管理，有英语，数学，c++成绩输入存盘，并对总成绩进行排名，还有各科的成绩分布情况统计。-Simple management of student achievement, there are English, Mathematics, c++ Accomplishments input disk, and a total score to rank, as well as the distribution of various statistical results.
2
- 07年数学建模b题，用C++做的，有一些瑕疵！不过总体说来不错-2007 Mathematical Modeling b title with C++ Do have some flaws! Overall, however good
pat7253596
- 电压带隙基准一个在模拟电路中很重的一部分，本文论述了带隙基准的一个高阶补偿方法-Bandgap reference voltage in the analog circuits in a heavy part of this paper, bandgap reference, a high-level compensation
Hanoi
- 一个Hanoi的小游戏 void Hanoi(int n, char x,char y,char z) { if (n==1) { printf("％c ％d ％c\n",x,n,z) return } Hanoi(n-1,x,z,y) printf("％c ％d ％c\n",x,n,z) Hanoi(n-1,y,x,z) }-Hanoi in a game void Hanoi (int n, char x, char