资源列表
rssxml
- 用java开发的RSS信息共享代码,可以将信息共享成XML,供RSS订阅工具订阅
graph-pb
- 利用PB做出图形化的范例,对编程人员非常重要-PB to make use graphical paradigm is very important for programmers
mianshi
- 牛叉公司面试题集之C和C++版本 著名IT企业面试题-Cow' s side cross examination questions set the C and C++ version of the well-known IT companies face questions
zy1
- watermarking in multiwvelet domain
VCtuxing1shibie
- vc 图像数字识别程序!!!vc 图形数字识别程序-vc digital image recognition program! ! ! vc graphics digital identification procedures! ! ! vc graphics digital identification procedures! ! !
ch01
- C++程序设计教程源代码,第一章,希望帮助大家-C++ programming tutorial source code, the first chapter, I hope to help you
19
- PHP简单实现的购物网站,仅供大家参考,谢谢!(It's easy to finish it ,I think you must can understand it, that all thank you!)
YY-批量签到助手
- 歪歪签到批量源码 专门提供给yy会有用户的(Sign in batch source code, specifically available to YY, there will be users)
粒子滤波算法
- 有关于粒子滤波综述的pdf,非常实用,大家可以下载来看看(Pdf, an overview of particle filtering, is very practical)
背包
- 给定n种物品和一背包。物品i的重量是wi,体积是bi,其价值为vi,背包的容量为c,容积为d。问应如何选择装入背包中的物品,使得装入背包中物品的总价值最大?在选择装入背包的物品时,对每种物品i只有两种选择,即装入背包或者不装入背包。不能将物品i装入背包多次,也不能只装入部分的物品i。试设计一个解此问题的动态规划算法,并分析算法的计算复杂性。(Given n items and a knapsack. The weight of the item I is wi, the volume is Bi
Hikvision camera detail
- how to use hikvision camera detail
Android-Terminal-Emulator-master
- Android Terminal Emulator