资源列表
jiqirenbizhang
- 界面有四个障碍物 机器人会自动躲开障碍物继续前进行走-There are four obstacles robot interface will automatically steer clear of obstacles continue to walk forward
pinpu
- 信号的频率选择性衰落,根据频率的不同,在某些点上信号增强,某些点上信号减弱,此代码为MATLAB建模的仿真代码,开发环境为matlabR2011B-The signal frequency selective fading
learn_const
- 该文件主要用于介绍C++中const的作用及其使用方法。-This document is mainly used to introduce c++ function and using method of const.
Cpp1
- 算数编码，输入一段二进制码，生成其算数编码，简单好学，适合初学者-Arithmetic Coding
whearth
- 抓取天气代码，抓取网页天气，不完善，供学习研究使用-c weather code
P_and_S_waves
- 纵波横波地震波动方程，形象的描述了纵波横波传播方向与质点振动方向之间的关系-seismic wave functions
statisticalremoval-
- 点云外部噪声去除，利用PLC软件，在VS2010平台-Point cloud outside noise removal, the use of PLC software, in VS2010 platform
RD_hanning
- 汉明窗有效提高雷达成像PSLR和ISLR，加窗函数作用在与提高主瓣抑制旁瓣-Han Mingchuang effectively improves the radar imaging of PSLR and ISLR, with a window function acting on the side lobe suppression with the enhancement of the main lobe
TriangleQuestion
- 该问题可描述为：对于给定的正整数n，按照2个同号下面都是+号，2个异号下面都是-号的规则生成符号三角形，计算有多少个不同的符号三角形，使其所含的+和-的个数相同。本程序使用回溯法解决符号三角形问题。-The problem can be described as: for a given positive integer n, in accordance with the with the No. 2 the following is+ number, two different numbers
102062342_714
- uva 714已經可以順利通過,並實現牛頓法找根-uva 714 already passed, and realized Newton' s method to find the root
Burg
- AR谱估计 burg 算法，用来求解功率谱-Burg algorithm for AR spectrum estimation
The-minimum-number-of-some-Numbers
- 求出一些数的最小数，如果读者有需求，可以自行更改。-The minimum number of some Numbers