资源列表
PointInPolygon
- 这是一个判断点是否在多边形内的很漂亮的算法。-This is a point to determine whether the polygon is very beautiful algorithms.
QPSK_BER
- DQPSK调制与解调后得到误码率曲线，与理论值很相近-DQPSK modulation and demodulation of the BER curves, very close to the theoretical value
mars_car_problem
- 这是一个用ruby写的经典火星车问题，其中包含了单元测试代码-This is a classic ruby write rover problem, which contains the unit test code
ex_7_11
- ABAQUS FORTRAN programming for random numerical process application
MultiThread2
- 很好的一款多线程实例哦 很适合初学者 里面有我精心准备的很多代码 简单实用-Good examples of a multi-threaded, oh it is suitable for beginners to have a lot of code inside my carefully prepared simple and practical
charnums
- 求一个字符串中连续出现的次数最多的子串[C语言实现]-The highest number of children seeking a consecutive string string [C language]
ezd000
- 用佐普利兹方程推导反射透射系数与入射角关系-Zoeppritz equation derived by reflection and transmission coefficient and the angle of incidence relations
jose
- 约瑟夫环（约瑟夫问题）是一个数学的应用问题：已知n个人（以编号1，2，3...n分别表示）围坐在一张圆桌周围。从编号为k的人开始报数，数到m的那个人出列；他的下一个人又从1开始报数，数到m的那个人又出列；依此规律重复下去，直到圆桌周围的人全部出列。通常解决这类问题时我们把编号从0~n-1，最后结果+1即为原问题的解。 -Josephus (Josephus problem) is the application of a mathematical problem: Given n indi
step_response
- 计算阶跃响应相关指标，包括超调量、上升时间、调整时间、稳态误差等，计算效果很好。- Calculate the step response-related indicators, including the overshoot, rise time, settling time, steady-state error, etc., is calculated with good results.
2.29
- 编程之美2015年初赛题目，主要判断闰年以及一些特殊边界。-Programming of the United States early in 2015 title game, the main judgment leap year as well as some special border.
Face-Detection-and-Eye-Detection-using-OpenCV-Tut
- FACE AND EYE DETECTION USING OPENCV
LongPlind_Remove
- 寻找回文子串是一道经典的面试题，本代码旨在解决字符可删情况下的寻找最长回文子串问题。-Finding the longest palindromic substring is one of the most typical face questions, the source code uploaded is aimed to finding the longest palindromic substring while the characters are removable.