资源列表
tmz1009
- 天门阵游戏源码。是类似连连看的一款游戏,需要通过鼠标拖动牌到相同牌对齐的地方后,消除。最多有30000局。-days Gate Array game source. 1000 block of Terry Avenue is similar to the one game, through licensing the mouse to drag the same alignment of licensing, eliminate. Up to 30,000 Bureau.
whoiam
- 猜猜我是谁游戏源码。照片图像逐步细化显示,在聚会时做游戏用-Guess Who game source. Photos gradually thinning, the gatherings do with the game
2000112503201
- 一款射击小游戏,包含游戏与源码,对编写大的设计游戏可能有帮助,谢谢参考研究-one shooting small game, including games and source code, for the preparation of the big game design might be helpful, thank reference research
llkhlp1002
- 连连看过关辅助程序。详细阅读readme.txt文件-1000 block of Terry Avenue auxiliary clearance procedures. Carefully read the readme.txt file
冒险游戏的编写和下拉式菜单的设计
- 冒险游戏的编写和下拉式菜单的设计 用C语言编写的小游戏以及下拉菜单-adventure games development and dropdown menus designs,small games and dropdown menus by c.
jylgame
- 一款vb编写的记忆力源程序,此程序特别适合初学者研究和学习-one prepared by the memory source, this procedure is particularly suited to study and learn from beginners
2005626101798340
- 这是传奇世界游戏服务器的源代码!里面共包括50个C++语方文件!-This is the world's legendary game server source code! They include a total of 50 C language to paper!
代码包含了所有的象棋游戏
- 很有趣的中国象棋游戏的源代码,与大家分享-very interesting chess game's source code to share with you
sorcecode
- 六级考试的时候编的,还包括了四个程序: 都是自己写的,一些参考了别人,本来还想上传一个大一时候的俄罗斯方块,结果没找着.老大现在功课太紧,我急需一个源程序,星期一就要交了,无论如何请放行.人都是会感恩的嘛.-six examination of the series, including the four procedures : all wrote it myself, some reference to the others, had wanted to upload a freshman
复件 Java象棋V3.0
- 小游戏可以实现象棋的各个功能比如象棋的各棋子的走法要求以及获胜后的提示,走棋时候的音乐效果-small chess game can be achieved in various functions such as chess pawn of the requirements of the law go after winning tips, and take time to the music game results
Delphi 组件编写--扑克牌组件
- 在网上看了不少关于扑克牌组件的编写,大多是调用Windows/system32下的cards.dll其实我们如果不调用这些函数也是可以作一个很好扑克牌组件。-online poker read many components of the preparation, most of the calls Windows/system32 cards.dll fact that if we do not call these functions would also be a very good po
Tetr_vc
- 这是一个俄罗斯方块的源程序,大家可以试一试-This is a Rubik's cube of the source, we can try