资源列表
11110
- 很好的人工只能实验程序哦，希望大家多多支持-Good artificial experimental procedures can only be Oh, I hope everyone can support
bbwt
- 遗传算法解决背包问题，即装入物体容量有限，每个物体有不同价值，使得最终价值最高。-Genetic algorithm to solve knapsack problem, namely the limited capacity of loaded objects, each object has a different value, making the final value.
CRC1
- CRC16, Table driven methods
big_number
- This program is to handle all possible arithmetic operations (+, -, *, /, ) and logic operations (<, >, >=, <=, ==, !=) between 2 numbers, which have quite a lot of number of digits.-This program is to handle all possible arithmetic opera
multiple_conversion
- To convert many different measurements. For example for feet to meters, and back. There is an easy menu that guides you to what you want.
Text1
- 哈弗曼编码译码器，输入一段英文文字 可以以实现哈弗曼译码-Harvard Manchester decoder coding, input a English word Can harvard to Manchester decoder
sve
- code for criteria function for lanching satelite
lzh
- 使用 RUNGE-KUTTA-FELBERG 的方法去解决y -e^(x)y -2y +y=e^(-x)*(2e^(-x)cos(x)+5sin(x)).这是一道比较经典的数值分析题目。-Use RUNGE-KUTTA-FELBERG solution to y' ' '-e ^ (x) y' '-2y '+ y = e ^ (-x)* (2e ^ (-x) cos (x)+5 sin ( x)). This is a classic comparison o
zz
- 使用Euler-Cauchy method方法去处理2个矩阵。y(x) = eAxy0这个是实际的函数-Euler-Cauchy method used to deal with two matrix. y (x) = eAxy0 this is the actual function
qq
- A numerical solution of the 2D wave equation utt = β2 (uxx + uyy) is required over the region R in the x, y plane R = {(x, y)| 0 < x < a, 0 < y < b}-A numerical solution of the 2D wave equation utt = β2 (uxx+ uyy) is required over
ww
- Modify the Matlab Gauss Elimination routine given in lectures so that it (a) performs implicit complete pivoting, and (b) handles m right hand sides at once by performing an LU decomposition of the matrix A first and then doing forward substitu
fr
- Write a Matlab program which solves the initial value problem y = (xy − y2)/x2, y(1) = 2, by the order four Runge-Kutta method, over the interval [1, 3] using steps of h = 1/128. The exact solution to this problem is given by y(x) = x/