资源列表
carpark
- 停车场管理 加实习报告 《数据结构》的课程实习报告，内容包括报告书写格式-Add parking management internship report " data structure" of the curriculum internship report, including report writing format
czs
- 1. 本程序实现计算任意长的整数的四则运算. 以用户和计算机对话的方式,先后输入数字的最多位数,然后程序就计算并显示出这两个数的运算. 2. 利用双向循环链表现实长整数的存储,每个结点含一个整形变量.输入的形式以回车结束,可以直接输入正数或负数,程序会过滤掉无效的字符.按中国对于长整数的表示习惯,每四位一组,除数字和位于首位置的负号外,其它一切字符都将作为分隔符,连续多个分隔符当一个处理.但不使用分隔符也不影响结果. -1. This procedure calculating the
stack_link
- 这是用链表实现的栈数据结构。链表数据结构的最大优点是不受元素个数的限制，除非内存耗尽。-This is the stack implementation with linked list data structure. List data structure is not subject to the greatest advantage of the restricted number of elements, unless the memory run out.
RegexTester.source
- 一个好用的正则表达式验证程序源码,可以参考-a regex tester source
horse
- 跳马问题，输出象棋跳马的多种的可能性结果-Horse problem, the output of a wide range of chess possibility vault results
0-1package
- 在0和1情况下进行背包问题解决，涉及多个物体的重量和价值，求得最大价值量以及分配方案。-At 0 and 1 backpack case for problem-solving, involving more than the weight of objects and values, as well as to achieve maximum value distribution program.
Rumore_rosa
- Pink noise generated in matlab
26102
- Shot 26102 I_plasma. Disruption
26001_td
- Shot 26001- I_pla - Ok Shot-Shot 26001- I_pla- Ok Shot
Rumore_bianco
- Earthquake magnitudo registered in San Francisco, during last 2 years plus white noise data
Maze
- 迷宫算法（maze） /* Maze * Starting point is m[0][0], need to find a path go to m[9][9]. 0 means OK, * 1 means cannot go there, boundary is 0 and 9, cannot go beyond boundary. * Each step can be made horizontally or vertically for one more gri
hangkong
- 航空订票系统的c++源码。是数据结构航空客运订票系统的源码，个人制造-Air booking system c++ source code. The structure of air passenger data source booking systems, personal manufacturing