资源列表
FastCodeAcquisition_and_Tracking_forDSPSS
- 讨论基于软件无线电技术的直接序列扩频码元捕获及跟踪的快速算-Discussion is based on software radio technology, direct-sequence spread-spectrum code yuan to capture and track the fast calculation
abc
- 单循环赛中选手胜负序列求解问题 名称:单循环赛中选手胜负序列求解问题 内容:有n个选手 P 1 ,P 2 ,P 3 ,… ,P n 参加了的单循环赛,每对选手之间非胜即负。现要求求出一个选手序列 P 1 ,P 2 ,P 3 ,… ,P n , 使其满足 P i 胜 P i+ 1 (i=1,… ,n-1) 。 -Single round robin tournament players winning sequence to solve the problem name: the ou
PackageAnalyzerV01
- 这是我珍藏的简单的封包分析工具,希望大家喜欢。-This is my collection of simple packet analysis tool, I hope everyone likes.
BPNetSample
- BP神经网络源代码,通过BP神经网络可进行各种模拟,特别是运算模拟都可以逼近-BP neural network source code
8num
- 八数码问题的简单算法,广度优先 字数补丁.exe-8 digital issues simple algorithm, breadth-first words patch. Exe
tspmatlab
- 31个城市的TSP问题,用蚁群算法编写的程序-TSP problem for 31 cities ,ACO program
AStar
- 实现的人工智能寻路算法 希望对大家有所帮助-AI pathfinding algorithm implementation we want to help
jiedianfenxifa
- 使用结点分析法求解直流电阻电路,并将结果保存在txt格式的文档中-The use of node analysis method to solve the DC resistance circuit, and the results saved in txt format document
rsa
- rsa&md5 公钥和私钥就是从两个文件PublicKey.xml、PrivateKey.xml中读取出来,相当于是现实中的指定公钥和私钥;再验证时我为了方便直接验证的A计算出的HASH码,现实中应该是由B重新计算出文件M的HASH码-ras&md5
juntuanwenti
- 军团问题, 某国家在一条战线上(一条直线)上部署了n 支军队。如果两支或两支以上军队相邻,它们将形成一个军团。如果一支军队不和任何一支军队相邻,那么它也是一个独立的团。给定一组军队在战线上左右两端的位置及编号,求出所有的军团 -Corps issues, a country in a front (a straight line) on n-support forces deployed. If two or more than two neighboring armies, they wi
getprob
- c program for identifying bottleneck machines in a job shop (used in the scheduling of the shop floor)
jj
- 使用VisualC++实现的伪逆矩阵的计算方法,Dlg编程。-Using VisualC++ implementation of the pseudo-inverse matrix method of calculation, Dlg programming.