资源列表
Esprit_try
- DOA估计的又一经典算法,和MUSIC相比,不需要谱峰搜索,相对更快捷!是利用空间旋转不变性求得波大方向。-DOA estimation is a classical algorithm, and compared to MUSIC, without spectral peak searching, relatively more efficient! Is the use of space rotation invariance to obtain the wave direction.
program-of-kalman
- 基于matlab的一个卡尔曼滤波器,对于理解卡尔曼滤波器有很好的作用-Have a good understanding of the Kalman filter based on a Kalman filter matlab
random walk 3d
- This demonstrates the concept of a 3d random walk. Brownian motion and a recursive markhov chain.
guihd
- 神经网络gui代码,具有仿真界面,简单易学,欢迎下载-Neural network gui code simulation interface, easy to learn, welcome to download
simulation_2psk
- 求出以dB为单位的给定比特信噪比的误符号率-Find the symbol error rate of a given bit signal-to-noise ratio in dB
chirp
- this code shows how to create a chirp .
mixedpath
- 拖拉机轨迹跟踪,拖拉机模型采用链式系统,算法为开环控制-Tractor trajectory tracking, tractor model uses a chain system for the open-loop control algorithm
ERADC
- 用于模态参数识别 可以识别频率和阻尼,利用eradc法,未列出振型识别的语句,可以自由添加 -For modal parameter identification Frequency and damping can be identified using eradc method, modal recognition statement is not listed, you can freely add
sim_langtu
- 首先计算狼的初始位置到兔子洞穴的直线距离: 由于狼奔跑的速度是兔子速度的两倍,兔子跑60码的时间狼可以跑120码。如果狼沿直线奔向兔窝,应该是可以追上兔子的。但是,有人推导出狼在追赶兔子过程中的运动曲线为 根据曲线方程,当 时, 。也就是说,在没有兔窝的情况下兔子一直往北跑,在跑到大约66码处将被狼追上。由此可知,在有兔窝时狼是追赶不上兔子的。 用计算机模拟的方法也可以得到同样的结论。取时间步长为1m,随时间步长的增加,考虑这一系统中的各个元素(狼和兔子)所处的位置变
finger-print-coding
- FINGER PRINT CODING IN MATLAB .. RECOGNIZATION OF FINGERPRINT CODING IN MATLAB CODING FOR COAMPANY USAGE
pmsys
- Phase Modulation matlab code
fuliye
- matlab 傅里叶变换 图像的傅里叶变换,利用快速傅里叶进行图像的频率分析然后画出图形-Matlab Fourier transform The Fourier transform of the image and of the image by using the fast Fourier frequency analysis and then draw the graphics