资源列表
oneD_hyex_sourceH_DNG
- 一维双负介质的drude等效模型的防真程序．可以从输出图象中看出双负介质的基本特性-one-dimensional negative media drude Equivalent Model defense really procedures. Images can be output seen double negative dielectric characteristics of the basic
threeD_sourceE_NearToFar
- 使用Matlab编制的3D－FDTD程序，程序中使用拉夫等效原理进行时谐场外推．程序中给出了阵子天线的注释代码．-using Matlab based 3D-FDTD procedures, procedures for the use of Lyford equivalence principle for the time-harmonic extrapolations. Procedures given the stream of the Notes code antenna.
3D-FDTD-Liao
- ３D-FDTD防真，边界为廖氏差分格式,程序使用计算机内存较少，可以用来做稍大尺寸物体的电磁防真-3D-FDTD defense truthfulness, Liao borders difference format, procedures use less computer memory. can be used to do slightly larger size object electromagnetic defense really
Xarchiver-0.3.3
- unix/linux下支持各种压缩算法的软件，支持gzip、7z、arj、rar、bzip-unix / linux to support various compression algorithm software, support gzip, 7z, arj. rar, bzip
p7zip_4.42
- 由7-zip提供的压缩、解压缩程序，支持7z/LZMA/BCJ/BCJ2，提供最高的压缩比-from 7-zip with the compression, decompression procedures, 7 z/LZMA/BCJ/BCJ2 support, providing the highest compression ratio
multiply(LJ)
- 用链表求300的阶乘,并且返回链表节点的个数.-used for the factorial 300, and returned to the linked list node number.
CMI
- 一个用VHDL编写的一个cmi解码编码程序。可以对数据进行编码技术。加密。-a VHDL prepared a cmi decoder coding process. The data can coding techniques. Encryption.
h.264_source
- h.264算法的源代码，具体适用于哪个个平台目前还不是很清楚-h.264 algorithm source code, which applies specifically to the platform is not yet clear
BPwavelet_0222
- 基于小波神经网络算法的流域日径流预报模型，该例程为结合型小波神经网络的例子-based on wavelet neural network algorithm watershed day runoff forecasting model, the combination of routines for wavelet neural network examples
advancesa
- 这是我自己做的改进的遗传算法，主要是克服遗传算法的早熟问题-This is what I want done to improve the genetic algorithm, which is aimed at overcoming the genetic algorithm early problems
cpbdesign
- 倍频程计算，在振动或噪声技术应用中经常用到的算法程序，是matlab源码-octave, the vibration or noise technology applications often use the algorithm process, the source Matlab
0-1beibao
- 解决背包的取舍问题，问选择多少个不超过背包的重量的物品．能使价值最大．-solve knapsack choice question about the choice of the number does not exceed the weight of the backpack items. Make the greatest value.