资源列表
20070609
- 高斯回代算法源代码 蚁群算法的matlab源码 蚁群算法TSP(旅行商问题)通用matlab程序 Java实现几种常见的排序算法 用pascal语言实现希尔排序算法-Gaussian back to the source code generation algorithm Ant Algorithm Matlab source Ant Algorithm TSP (TSP) General Matlab procedures Java Several ranking algori
Findstr
- 字符串的kmp模式匹配，分别输入主字符串和模式字符串，输出匹配结果-kmp string pattern matching, the main input strings and string mode, the output matching results
HashFM1
- 散列文件的操作，四个操作：向散列中插入一个元素，删除一个元素，查找散列中的元素，输出散列元素等。-hash document, the operation of four operators : to insert a hash elements, delete an element Search hash of elements, such as elements of the output hash.
erfenfa2
- 非递归调用的二叉查找法：初始化一个数组，提示输入待查元素，返回查找的结果和查找次数-non - recursive call the binary search method : an array initialization, suggesting that the importation of unknown origin elements, return to the search results and the number of search
kuaisufa3
- 快速排序算法：初始化一个数组，并演示出排序的过程，给出排序后的数组进行比较。-Quick Sort Algorithm : an array initialization, and demonstrated the process of sorting out. given sorting arrays were compared.
ProblemB
- 给出不同的匹配的分数，求两个序列匹配的最大分数-given different matching scores for the two largest sequence matching scores
bianldeyouyngi
- 进行图的遍历的演示,（c 语言 数据结构课程设计题）,绝对有用,可以运行-plans for the traversal of the display, (c language curriculum design data structures that), absolutely useful, can run
05060213
- lianbiao shixian bu hao yi si gang bian de-lianbiao shixian bu hao yi bian de si gang
RaidersotheLostArk
- 福建师范大学第三届程序设计比赛中的一道试题.用回溯法解决.-third Fujian Normal University Design Competition of an item. With retroactive law.
Horse-zym
- C# 写的马周游算法。包含实验报告！请注意修改名字哦-C# to write a horse around the algorithm. Experimental report contains! Please note the name change oh
haffman_tree
- 我的一次数据结构课程设计HUFFMAN树的C++源代码，基本功能有： 1.显示27个字符的haffman编码； 2.输入m个字符，对应27个字符的权值进行haffman编码； 3.输入一串字符，用已经定义的haffman编码输出；-a data structure course design Speed HUFFMAN tree C source code, the basic function : 1. show 27 characters haffman coding; 2. m
1111345455
- 按照清华大学的那本数据结构的表达式求值改进-according to the Tsinghua University that the data structure of the expression evaluates to improve