资源列表
algs4
- 算法（第四版）随书源码，JAVA语言实现，经典-Source codes of Algorithms(4th edition), which is realized in JAVA and quite classical
zhongxinchafen
- 通过中心差分方法简单计算振动系统的响应。-The response of the vibration system is simply calculated by the central difference method.
demo
- Vc++完整源码：实现二叉树的建立与先序遍历-Build Binary Tree
BFS-algorithm-learning
- BFS经典算法，准备比赛时自己写的，一看即懂。里面有比较详细的算法介绍，可供学习参考。-BFS classic algorithm, ready to play when they write, a look that is to understand. There are more detailed algorithm introduced, available for study and reference.
permutations-and-combinations
- 经典DFS排列组合算法，简洁代码极易懂，使用DEV编写并编译，参加算法比赛必备算法- Classic DFS permutations and combinations algorithm, concise code is very easy to understand, the use of DEV to prepare and compile, to participate in the algorithm game algorithm
HeapSort
- 堆排序非递归实现 代码注释详细，简单易懂-heapsort no recursion
reshensaibiaocheng
- 计算客第二届计算之道比赛的热身赛标程，在官方qq群拿到的-Calculated off the second channel calculation of the standard process warm-up match
sort
- 任意输入两个大的整数并以Q结尾，然后对输入的数字进行排序，并按从小到大的顺序输出-Enter any two large integers and Q at the end, and then sort of digital inputs, according to the order small to large output
project
- 输入一个数判断是否为萨姆斯浪数，也就是说输入的数字是否等于没位数的N次方之和，其中N为此数的位数-Enter a number to determine whether the Sams wave number, that is to say the digital input is equal to the number of bits of the N-th power is not the sum of the number of bits where N is the number fo
sort1
- 任意输入几个数字，并以Q或者q结尾，然后判断这几个数的大小，并又小到大输出-Any input a few numbers, and Q or q at the end, and then determine the size of these numbers, and to large and small output
Program
- 利用表达式求解和栈的只是，设计一个简易的数学题库， 可供小学生作业，并能给出分数。 要求：建立试题库文件，随机产生 n 个题目；题目涉及加减乘除，带括弧的混合运算；随时可以退出；保留历史分数，能回顾历史，给出与历史分数比较后的评价。-Use solving expressions and stack just design a simple math exam, students for the job, and can give a score. Requirements: Creat
MyRsa
- 这是rsa 的程序解释，实现了rsa的功能，密码学的基础-rsa program explained, implements rsa functions based cryptography