资源列表
dazhengshujiafa
- 子函数允许任意长度的被加数，被加数和结果都是字符串，可以直接输出。-Subroutine allow arbitrary length summand, summand, and the result is a string, you can output directly.
dd
- shell sort is a rather curious algorithm, quite different from other fast sorting algorithms. It s actually so different that it even isn t an O(nlogn) algorithm like the others, but instead it s something between O(nlog2n) and O(n1.5) depending on i
ouler
- 微分方程数值解中利用Runge-kutta_fehlberf法计算微分方程 -Numerical solution of differential equations using Runge-kutta_fehlberf differential method
jacobi
- 雅克比迭代法，运行方便，对于程序员可能会有非常大的帮助-Jacobi iterative method
transcendental_equation_Newton
- transcendental equation, Newton method
simul_abu3
- This program is written in matlab. It uses the basic knowledge of Crammers Rule and applies it to write the step-by-step solution of three simultaneous linear equations in three unkowns.
Romberg
- Romberg算法运用C++程序的实现，只要修改被积函数，可以直接求积分-Romberg algorithm using C++ program implementation, as long as the changes have been integrated function, can be directly quadrature
add_2x32_v1
- 2*32乘法器设计，只是部分Booth乘法器的设计，相关的后面部分将在需要时陆续上传。-design of an 2*32Multiplier
Analytic-hierarchy-process-AHP-
- 本代码是数学建模中常用的方法层次分析法的常用程序，对解决评价模型是十分重要的模型。-This code is commonly used mathematical modeling methods commonly used analytic hierarchy process, evaluation of the model is very important to solve the model.
Fourth
- 利用随机函数产生5道两位数的加法题，每答对一道得20分，答错不得分，最后判断用户的总得分并输出。 提示：产生两位随机数用以下办法 int x=(int)(10+Math.random()*90) -The random function of five double-digit addition problems, and for each correct answer a 20 points, got it wrong not scoring, the final judgmen
MT-simulation
- 基于舍选法的蒙特卡洛抽样模拟超标准洪水，只要输入站点的平均流量，Cv和Cs即可进行重复抽样。-Rejection method based on Monte Carlo simulation of super-sampling standard flood, just enter the site s average flow, Cv and Cs can be repeated sampling.
MyShuffleTest
- Suppose we start with N=3 and run the shuffling test four times, resulting in the arrays: [2, 0, 1] [2, 1, 0] [2, 0, 1 ] (This not very likely, but i s possible) Then the resulting count array would be: 0: 0 3 1 1: 0 1 3