一次大型的party最后节目是选取一位幸运人士，该人将获得组织者准备的一个钻石戒指。选择办法是让所有人一字排列，然后从左至右点数，凡是奇数号的全部删除。对剩下的人，同样从左至右点数，逢奇数号就删除。如此不断循环，直到只剩1人为止。此即为幸运之人。-A large party last program is to select a lucky person, that person will get the organizers to prepare for a diamond ring. Option is to arrange all of the word, then points from left to right, all odd numbers deleted. On the left, the same points from left to right, every odd number to delete. This constant cycle, until only one person so far. Namely for the lucky person.