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求三角对角方程组Tx=f的解,其中T=[1 1 0 0 0,1 2 1 0 0,1 1 3 1 0,0 0 1 4 1, 0 0 0 1 5],x
=[x1,x2,x3,...x5],f=[3,8,15,24,29]-Diagonal triangle demand equations Tx = f the solution, in which T = [1 1 0 0 0,1 2 1 0 0,1 1 3 1 0,0 0 1 4 1, 0 0 0 1 5], x = [ x1, x2, x3, ... x5], f = [3,8,15,24,29]
=[x1,x2,x3,...x5],f=[3,8,15,24,29]-Diagonal triangle demand equations Tx = f the solution, in which T = [1 1 0 0 0,1 2 1 0 0,1 1 3 1 0,0 0 1 4 1, 0 0 0 1 5], x = [ x1, x2, x3, ... x5], f = [3,8,15,24,29]
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3/3求三对角方程组Tx=f.doc
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3/Tss.m
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