import java.io.* public class SquareRoot { public static void main ( String [ ] args )

{ System.out.print("Enter a positive value: ") double value = 0 try { BufferedReader in

= new BufferedReader(new InputStreamReader(System.in)) String inputLine = in.readLine()

value = Double.valueOf(inputLine).doubleValue() } catch (Exception exc)

{ System.out.println("Input error!") return } if (value < 0) System.out.println("Input

error!") else { double root = 1 double pre = 0 do { pre = root root = (value / root +

root) / 2 } while ((pre - root > 0.000001) || (root - pre > 0.000001)) System.out.println("The

root of " + value + " is " + root) } } }

你容易理解这个程序吗？在计算机上运行该程序，看看该程序完成什么功能？尝试利用

分行、缩进、空行、空格等为该程序重新排版，并加上合适的注释。（提示：所谓程序的排

版不同于WPS 2000 那种对文档的排版，后者主要是对字体、字形、字号、字间距、行间距等格式的处理。

-Import Java. IO.*　Public class SquareRoot {public static void main (String [] args)

{System. Print out. (" Enter a positive value: ")　Double value = 0　Try {BufferedReader in

= new BufferedReader (new InputStreamReader (System..))　String inputLine = in. ReadLine ()

Value = Double. ValueOf (inputLine). DoubleValue ()　} catch (Exception exc)

{System. Out. Println (" Input error! ")　Return　} if value (< 0) System. Println. (" Input out

Error!!!!!")　else {double root = 1　double pre = 0　do {pre = root　root = (value/root+

Root)/2 } while ((pre-root > 0.000001) | | (root-pre > 0.000001))　System. Out. Println (The "

Root of "value++" is "+ root) }}}

You easy to understand this program? On the computer to run the program, check to see if the program finish what function? Try to take advantage of

Branch, indentation, empty line for the program, such as space to typesetting, and add the right note. (hint: the so-called program row

Version is different from that of d