文件名称:example3
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- 上传时间:2012-11-16
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文件大小:877.86kb
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三维Sierpinski镂垫的递归程序,使用三维点,由于每个四面体都是凸性的,因此四面体的顶点与其内部任意点肯定在四面体内部-3D Sierpinski router pad of the recursive procedure, using a three-dimensional point, because each tetrahedron is convex, so the tetrahedral vertex and any point must be in the tetrahedral interior
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下载文件列表
example3/debug/example3.exe
example3/debug/example3.ilk
example3/debug/example3.pdb
example3/example3/Debug/BuildLog.htm
example3/example3/Debug/example3.exe.embed.manifest
example3/example3/Debug/example3.exe.embed.manifest.res
example3/example3/Debug/example3.exe.intermediate.manifest
example3/example3/Debug/example3.obj
example3/example3/Debug/example3.pch
example3/example3/Debug/mt.dep
example3/example3/Debug/stdafx.obj
example3/example3/Debug/vc80.idb
example3/example3/Debug/vc80.pdb
example3/example3/example3.cpp
example3/example3/example3.vcproj
example3/example3/example3.vcproj.PC-201002061541.Administrator.user
example3/example3/ReadMe.txt
example3/example3/stdafx.cpp
example3/example3/stdafx.h
example3/example3.ncb
example3/example3.sln
example3/example3.suo
example3/example3/Debug
example3/debug
example3/example3
example3
example3/debug/example3.ilk
example3/debug/example3.pdb
example3/example3/Debug/BuildLog.htm
example3/example3/Debug/example3.exe.embed.manifest
example3/example3/Debug/example3.exe.embed.manifest.res
example3/example3/Debug/example3.exe.intermediate.manifest
example3/example3/Debug/example3.obj
example3/example3/Debug/example3.pch
example3/example3/Debug/mt.dep
example3/example3/Debug/stdafx.obj
example3/example3/Debug/vc80.idb
example3/example3/Debug/vc80.pdb
example3/example3/example3.cpp
example3/example3/example3.vcproj
example3/example3/example3.vcproj.PC-201002061541.Administrator.user
example3/example3/ReadMe.txt
example3/example3/stdafx.cpp
example3/example3/stdafx.h
example3/example3.ncb
example3/example3.sln
example3/example3.suo
example3/example3/Debug
example3/debug
example3/example3
example3
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