阻尼牛顿法求解minf(x)=(1-x1)^2+2*(x2-x1^2)^2初始点x=(0,0)精度为0.01。可运行出结果,程序清晰,算法明确。-Damped Newton method for solving min f (x) = (1-x1) ^ 2+2* (x2-x1 ^ 2) ^ 2 the initial point x = (0,0) accuracy of 0.01.It Can run out the results 。 the program is clear,　algorithm is explicit.