请编一个函数fun(int *a,int n,int *odd,int *even)，函数的功能是分别求出数组中所有奇数之和以及所有偶数之和。形参n给出数组中数据的个数；利用指针odd返回奇数之和，利用指针even返回偶数之和。-Please make up a function fun ( int* a, int n, int* odd, int* even ), functions are respectively derived array all odd and even and all. The parameter n gives the number of array data pointer　use odd return of odd number, using the pointer even returns the sum of.